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Mrrafil [7]
2 years ago
15

Write an exponential function for a graph that passes through the points (2, 1.4) and (4,5.6)

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
6 0
<h2>effsd and i cant do it</h2>
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Can 45/9 be simplified?
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yes to 5

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What is the length of DE
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Which term best describes the system of equations?
Oduvanchick [21]

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  coincident

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The first equation is 3 times the second equation, so describes exactly the same line. The lines are "coincident".

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Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0
3 years ago
Identify the contrapositive of the following statement. If x = 2, then x + 3 = 5.
antiseptic1488 [7]

Answer:

If x + 3 ≠ 5, then x ≠ 2 thus b: is your Answer

Step-by-step explanation:

4 0
3 years ago
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