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Taya2010 [7]
4 years ago
8

The _____, a subcortical brain structure crucially involved in storing new information in memory, is smaller in people with schi

zophrenia and their first-degree relatives (parents and siblings) than in control participants.
Computers and Technology
1 answer:
pashok25 [27]4 years ago
6 0

Answer:

The hippocampus, a subcortical brain structure crucially involved in storing new information in memory, is smaller in people with schizophrenia and their first-degree relatives (parents and siblings) than in control participants.

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The refresh or reload button is in the browser toolbar and usually looks like a pair of curved arrows. Clicking it will ________
docker41 [41]

Your answer would be

D. Restart the downloading process

5 0
4 years ago
Read 2 more answers
Write a recursive method to return the number of uppercase letters in a String. You need to define the following two methods. Th
satela [25.4K]

Answer:

<u>Recursive function with two parameters that return the number of uppercase letters in a String</u>

public static int count(String str,int h)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          h++; //incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1),h);//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1),h); //recalling function

      }

      return h;

  }

This is the recursive function with the name count of return type integer,having parameters str of string type and h of integer type.In this we are checking the characters at a particular position from A to Z.

<u>Recursive function with one parameter that return the number of uppercase letters in a String</u>

public static int count(String str)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          count++; //incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1));//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1)); //recalling function

      }

      return count;

  }

This is the recursive function with the name count of return type integer,having parameters str of string type .In this we are checking the characters at a particular position from A to Z.

<u>Java program that return the number of uppercase letters in a String</u>

import java.util.*;

public class Myjava{

static int count =0;//Defining globally  

 

public static int count(String str,int h)//Defining function

{

      if(str.charAt(0)>='A' && str.charAt(0)<='Z')//Checking the characters from A to Z

{

          h++;

//incrementing the counter

          if(str.length()>=2){

              return count(str.substring(1),h);//recalling function

          }

      }

      if(str.length()>=2){

              return count(str.substring(1),h);

//recalling function

      }

      return h;

 

  }

  public static void main(String[] args)//driver function

  {

      System.out.println("Enter a string");//taking input

      Scanner scan = new Scanner(System.in);

      String s = scan.nextLine();

      int h =0;

      System.out.println("Counting the Uppercase letters: "+count(s,h));

  }

}

<u>Output</u>

Enter a string  WolFIE

Counting the Uppercase letters: 4

4 0
3 years ago
Characteristics of successful entrepreneurs include
crimeas [40]
The answer would be A because grit means to fight hard to get what you want. Submission would be to give in to pressure and give up. Self-importance would be to only focus on yourself and no one else. A short attention span would not work out for you because you get distracted easily.
8 0
4 years ago
A(n) ____________________ is the collection of individuals responsible for the overall planning and development of the contingen
RSB [31]

Answer:

Contingency Planning Management Team (CPMT)

Explanation:

:)

3 0
3 years ago
Given six memory partitions of 300 KB, 600 KB, 350 KB, 200 KB, 750 KB, and 125 KB (in order), how would the first-fit, best-fit,
Inga [223]

Answer:

In terms of efficient use of memory: Best-fit is the best (it still have a free memory space of 777KB and all process is completely assigned) followed by First-fit (which have free space of 777KB but available in smaller partition) and then worst-fit (which have free space of 1152KB but a process cannot be assigned). See the detail in the explanation section.

Explanation:

We have six free memory partition: 300KB (F1), 600KB (F2), 350KB (F3), 200KB (F4), 750KB (F5) and 125KB (F6) (in order).

Using First-fit

First-fit means you assign the first available memory that can fit a process to it.

  • 115KB will fit into the first partition. So, F1 will have a remaining free space of 185KB (300 - 115).
  • 500KB will fit into the second partition. So, F2 will have a remaining free space of  100KB (600 - 500)
  • 358KB will fit into the fifth partition. So, F5 will have a remaining free space of 392KB (750 - 358)
  • 200KB will fit into the third partition. So, F3 will have a remaining free space of 150KB (350 -200)
  • 375KB will fit into the remaining partition of F5. So, F5 will a remaining free space of 17KB (392 - 375)

Using Best-fit

Best-fit means you assign the best memory available that can fit a process to the process.

  • 115KB will best fit into the last partition (F6). So, F6 will now have a free remaining space of 10KB (125 - 115)
  • 500KB will best fit into second partition. So, F2 will now have a free remaining space of 100KB (600 - 500)
  • 358KB will best fit into the fifth partition. So, F5 will now have a free remaining space of 392KB (750 - 358)
  • 200KB will best fit into the fourth partition and it will occupy the entire space with no remaining space (200 - 200 = 0)
  • 375KB will best fit into the remaining space of the fifth partition. So, F5 will now have a free space of 17KB (392 - 375)

Using Worst-fit

Worst-fit means that you assign the largest available memory space to a process.

  • 115KB will be fitted into the fifth partition. So, F5 will now have a free remaining space of 635KB (750 - 115)
  • 500KB will be fitted also into the remaining space of the fifth partition. So, F5 will now have a free remaining space of 135KB (635 - 500)
  • 358KB will be fitted into the second partition. So, F2 will now have a free remaining space of 242KB (600 - 358)
  • 200KB will be fitted into the third partition. So, F3 will now have a free remaining space of 150KB (350 - 200)
  • 375KB will not be assigned to any available memory space because none of the available space can contain the 375KB process.
8 0
3 years ago
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