Solution-
Capacity of the spherical tank = 800 gallons.
1 gallon = 0.1337 ft³,
Volume of 800 gallons = 800 × 0.1337 = 106.96 ft³
Formula for the volume of sphere
Equating both the volumes
⇒ 
= 106.96
⇒ 
= 25.53
⇒ ![r = \sqrt[3]{25.53}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B25.53%7D)
⇒ r = 2.94
∴ Radius of the sphere is 2.94 ft
Apples went up 0.75 a lb
p is the start price so new price is p + 0.75
we buy 3 lbs
3 ( p+ 0.75) = 5.88
now solve
3p + 2.25 = 5.88
-2.25 -2.25
3p = 3.63
/3 /3
p = 1.21 a lb
Answer:
10.8 units
Step-by-step explanation:
The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.
sec(<em>x</em>) = csc(<em>x</em>)
By definition of secant and cosecant,
1/cos(<em>x</em>) = 1/sin(<em>x</em>)
Multiply both sides by sin(<em>x</em>) :
sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)
As long as sin(<em>x</em>) ≠ 0, this reduces to
sin(<em>x</em>)/cos(<em>x</em>) = 1
By definition of tangent,
tan(<em>x</em>) = 1
Solve for <em>x</em> :
<em>x</em> = arctan(1) + <em>nπ</em>
<em>x</em> = <em>π</em>/4 + <em>nπ</em>
(where <em>n</em> is any integer)
In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of
<em>x</em> = <em>π</em>/4 <u>or</u> <em>x</em> = 5<em>π</em>/4
Answer:
what
Step-by-step explanation:
