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morpeh [17]
3 years ago
8

A lighting fixture manufacturer has daily production costs of C = 0.25n^2 - 10n + 800, where C is the total daily cost in dollar

s and n is the number of light fixtures produced. How many fixtures should be produced to yield a minimum cost? What is the minimum cost?
Please Show All Of Your Work!
Mathematics
1 answer:
WITCHER [35]3 years ago
3 0

Answer:

The minimum value occurs at 20 fixtures and is $700

Step-by-step explanation:

C = 0.25n^2 - 10n + 800

to find the minimum we need to find the vertex

this parabola opens upwards, so the minimum is at the vertex

the vertex is at h=-b/2a  where an^2 +bn+c

h = -(-10)/2*.25

h = (10/.5)

h= 20

the n value of the vertex is at 20

the find the C value, we substitute this into the equation

c(20) = .25 (20)^2 -10(20) + 800

C(20) = .25 (400) - 200 + 800

C(20) = 100 -200+800

C(20) = 700

The minimum value occurs at 20 fixtures and is $700

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Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20
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P_{20} = \frac{20 * 9}{100}

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P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)

P_{20} = 16 + 0.8*(21 - 16)

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Solving (b): The 25th percentile

This is calculated as:

P_{25} = 25 * \frac{N +1}{100}

P_{25} = 25 * \frac{8 +1}{100}

P_{25} = 25 * \frac{9}{100}

P_{25} = \frac{25 * 9}{100}

P_{25} = \frac{225}{100}

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This is then calculated as:

P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)

P_{25} = 21 + 0.25(24-21)

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Solving (c): The 65th percentile

This is calculated as:

P_{65} = 65 * \frac{N +1}{100}

P_{65} = 65 * \frac{8 +1}{100}

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P_{75} = 75 * \frac{8 +1}{100}

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