Answer:
D. a reflection in the y-axis, followed by a counterclockwise rotation of 270 about the origin
Step-by-step explanation:
Well, the first obvious step is to reflect it across the y-axis. Now, for the next step, since we do not have a <em>90°-clockwise rotation </em>option, we have to go with something similar to that, which would be a <em>270°-counterclockwise</em> <em>rotation</em><em>.</em><em> </em>If you think about it, since 3 × 90 is 270, and rotating this figure 90° clockwise [one rotation] would go from Quadrant III to Quadrant II, going the other way around [270°counterclockwise (three rotations)] will also go from Quadrant III to Quadrant II [to Quadrant IIII to Quadrant I to Quadrant II].
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Answer:
The equation of the line has a slope of -5 and passes through the point (2, 2) is y = -5x + 12 .
Option (D) is correct.
Step-by-step explanation
The equation of the line
y = mx + c
where m is the slope and c is the y - intercept .
As given
A line has a slope of -5 and passes through the point (2, 2).
The slope of the line is -5.
m = -5
Put in the equation of the line
y = -5x + c
Put x = 2 and y = 2
2 = -5 × 2 + c
2 = - 10 + c
2 + 10 = c
12 = c
Put the value of c in the y = -5x + c
y = -5x + 12
Therefore the equation of the line has a slope of -5 and passes through the point (2, 2) is y = -5x + 12 .
Option (D) is correct.
Okay. So, one temperature is positive and the other one is negative. Let’s find the absolute value (distance from 0) for both numbers. -21 is 21 units away from 0 and 6 is 6 units away from 0. 21 + 6 = 27. The difference of temperature from 8 AM to 9 AM is 27 degrees.
