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aivan3 [116]
3 years ago
13

X^2 -6x - 15 = 0 complete the square

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0

Answer:

(x - 3)^2 = 24.

Step-by-step explanation:

x^2 -6x - 15 = 0

(x - 3)^2 - 9 - 15 = 0

(x - 3^2 -24 = 0

(x - 3)^2 = 24.

blondinia [14]3 years ago
5 0

Recalling that

(x-a)^2=x^2-2ax+a^2

Let's compare the middle term:

-6x = -2ax \iff a=3

So, we want to complete

(x-3)^2 = x^2-6x+9

Which differs from x^2-6x-15 by 24. So, if we add 24 to both sides, we have

x^2-6x-15=0 \iff x^2-6x+9=24 \iff (x-3)^2=24

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\displaystyle\int_{x=a}^{x=b}\int_{y=a}^{y=b}\frac x{(4+xy)^2}\,\mathrm dy\,\mathrm dx=\int_{x=a}^{x=b}\int_{u=4+ax}^{u=4+bx}\frac1{u^2}\,\mathrm du\,\mathrm dx
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Of course, this all assumes that the integrand is continuous over the domain of integration, which would require that a,b are chosen such that xy\neq-4 for any (x,y)\in[a,b]^2. If in particular ab>-4, then we can write

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