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myrzilka [38]
3 years ago
11

Draw a line through the origin that has a slope of 4/3

Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u><em>and the line passes through the origin</em></u>

In this problem the given line represent a proportional relationship, because passes through the origin

we have

k=\frac{4}{3} --->  the constant of proportionality k is equal to the slope

substitute

The linear equation is

y=\frac{4}{3}x

To draw a line we need two points

we have (0,0)

To find the other point

assume  x=3 and substitute in the equation to solve for y

y=\frac{4}{3}(3)=4

so

The other point is (3,4)

using a graphing tool

Plot the points (0,0) and (3,4)

To graph the line join the points

see the attached figure

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What is the ratio of one hour to 600 seconds?
Marat540 [252]

Answer:

6:1

Step-by-step explanation:

1 hr= 60 minutes

60 minutes= 3600 seconds

3600:600

36:6

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Find the area of the trapezoid.
vlabodo [156]

Answer: A.90 cm^2

Step-by-step explanation: A= a+b/2 h

A= 17.5+12.5/2 *6

A = 30/2*6

A= 15*6

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Find the term indicated in the expansion. (x - 3y)11; 8th term
Alja [10]
The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11,  k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
 =( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1  )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
 
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Which is a graph of the equation y = 2x- 4
algol13
The first one because the slope is 2/1 and y-intercept is -4
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Find the quadratic function that fits the following data. which one function fits.
Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c

We get the system of three equations:

\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.

Subtract these equations:

\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.

From the first equation

b=-120a

Substitute it into the second equation:

5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5

So,

2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25

The quadratic function is

y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25

4 0
3 years ago
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