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3 years ago

Solve for x in the following: 8x^2 + 6x = -5

Mathematics

1 answer:

artcher [175]3 years ago

8 0

Answer:

No solution or

(-3± $2i\sqrt{31}$ )/8

Step-by-step explanation:

To get the solution, move everything to the left side of the equation:

8x²+6x+5 = 0

If you try to factor the equation or graph it, you will see that it will never equal 0.

If you need an imaginary solution you can plug it into the quadratic equation:

-6± $\sqrt{36-160}$ over 16

Simplify and you get

-6± $i\sqrt{124}$ over 16

-6± $4i\sqrt{31}$ over 16

Simplify the fraction and you can get

(-3± $2i\sqrt{31}$ )/8

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Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest w

pishuonlain [190]

Answer:

59 feet per second

Step-by-step explanation:

(40m)(5280ft)=211,200 ft/hr
(211,200 ft/hr )=(211,200ft/3600s)
58.7 ft/s

6 0

2 years ago

Read 2 more answers

The price of a company's share dropped by 3.50% by the end of the first year, down to $44.25. During the second year the price o

omeli [17]

Answer:

a. $45.86

b. $43.87

c. Percentage change = -4.40%)

Step-by-step explanation:

a. Let the price of share at the beginning of first year be represented with X

Now, Price of company's share dropped by 3.50% at the end of first year.

So, Price of share at the end of first year = x - 3.5% of x

= x - 0.035x

= 1x - 0.035x

= 0.965x

But it is equal to $44.25

=> 0.965x = 44.25

x = 44.25 / 0.965

x = 45.8549223

x = $45.86

b. During second year price of share decreased by $1.99. Therefore, Price of share at the end of second year = $45.86 - $1.99 = $43.87

c. Percentage change in the price of shares over two years = {(45.86 - 43.87)/45.86} *100

= (1.99/45.86)*100

= 0.04339294 * 100

= 4.40%

Now, as price of shares has dropped, the percentage change will be negative. (Δ% = -4.40%)

5 0

2 years ago

Can any kind soul help me ASAP!

CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172 Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6= $\frac{167*x+3038}{19+x}$

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

3 0

3 years ago

What does it mean when someone asks you to diagram a statement in math?

kipiarov [429]

Answer:

A math diagram is any diagram that conveys mathematical concepts. This includes basic charts and graphs as well as sophisticated logic and geometrical diagrams. ... Mathematical diagrams are often created to illustrate concepts in textbooks or for presentation posters used at conferences.

Step-by-step explanation:

7 0

2 years ago

How do I solve for x

Bond [772]

Answer:

you have to figure out how big the angle is and then add the 38 and 21 and subtract that from the total i dont know if any of that made sense

Step-by-step explanation:

8 0

2 years ago