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jarptica [38.1K]
3 years ago
15

Plzzz help will give the brainliest for correct answer

Mathematics
2 answers:
kap26 [50]3 years ago
3 0
The answer would be ten.
The Pythagorean theorem is a squared plus b squared equals c.
c would equal the hypotenuse.
b is the opposite.
a is the adjacent.
you would do 24 squared plus x squared = 26 squared
after you square 24 and 26
576+x=676
-576.    -576
-----------------
x=100
square root it to get 
x=10
d is your answer
stira [4]3 years ago
3 0
A²+b²=c<span>²
</span>24²+b²=26<span>²
576+b</span>²=676<span>² </span>    
676-576=100
b²=100
Then you square root 100.
b=10
Your answer is 10!

Hope that helps! :D
 
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t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

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Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

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Step-by-step explanation:

Data given and notation

\bar X_{1}=6.5 represent the sample mean for Atlanta

\bar X_{2}=6.7 represent the sample mean for Chicago

s_{1}=0.5 represent the sample deviation for Atlanta

s_{2}=0.7 represent the sample standard deviation for Chicago

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n_{2}=110 sample size for the group Chicago

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis:\mu_{1}=\mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

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