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anygoal [31]
2 years ago
14

The gas tank in Ms. Brown's car holds 16 gallons. The gas tank in Mrs. Baylis car holds 25% than Ms. Brown's car. How much gas d

oes Mrs. Baylis car hold?
Mathematics
2 answers:
Vera_Pavlovna [14]2 years ago
4 0
Mrs brown =16gallons
25%=1/4
16g/4=4g

So you will either need to add or subtract 4gallons to find out what’s mr Baylis car holds you haven’t said if mr Baylis car contains more or less so
Alex_Xolod [135]2 years ago
4 0

Answer:

20 or 12 depends.. read the step by step

Step-by-step explanation:

If it is 25% more than Ms. Brown, then the answer is:

\frac{125}{100}×16 which is 20

OR

If it is 25% less than Ms. Brown, then the answer is

\frac{75}{100}×16 which is 12

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It cost Evan $17.70 to send 177 text messages how many text messages did he send if he spent $19.10
tatuchka [14]
He sent 191 text messages
3 0
3 years ago
In circle C, SQ = 10 cm. Which statements about the circle are correct? Check all that apply.
lbvjy [14]

Answer: A, B, D, E

Arc PQ is congruent to arc SR.

The measure of arc QR is 150°

Arc PS measures about 13.1 cm.

Arc QS measures about 15.7 cm.

Step-by-step explanation:

4 0
2 years ago
At a financial institution, a fraud detection system identifies suspicious transactions and sends them to a specialist for revie
labwork [276]

Answer:

a. E(X) = 54.4

b. E(X) = 2.5

c. P(Y=2) = .0116

Step-by-step explanation:

a.

    E(X) = np = .40 probability * 136 trials = 54.4 blocked transmissions

    To get the expected value, we simply multiply probability times number of trials. You can look at it in simple terms by thinking if there's a 50% chance of flipping heads and you flip a coin twice, in an ideal world you will have .5*2 = 1 head.

b.

    i. Let X represent the number of suspicious transmissions reviewed until finding the first blocked one. We will use a geometric distribution to model the "first" transmission. Whenever we're looking for the "first" time something happens, we use geometric.

   ii. E(X) = 1/p , according to the geometric model.

              = 1/.4 = 2.5.

       We expect that the specialist will review 2.5 suspicious transactions <em>on average </em>before finding the first transmission that will be blocked.

c.

    i. Let Y represent the exact number of blocked transmissions out of 10. We will use a binomial distribution to model the "fixed" number of transmissions. Whenever we're looking for a "fixed" number of times something happens, we use binomial.

    ii. P(Y=k) = (n choose k)(p^k)(q^n-k)

        P(Y=2) = (¹⁰₂)(.4^2)(.6^10-2)

                    = 45 (.4^2)(.6^10-2) = .0016

        As for calculator notation, the n choose k can be accessed on a TI-84 via MATH -> PRB -> nCr. It looks like 10 nCr 2 on the display.

        Hence the probability that two transactions out of ten will be blocked is .0016 by the binomial model.

5 0
3 years ago
What is the probability of spinning a D or a E, if The Spinner is spun how 100 times
lisov135 [29]

Answer:

About 50, 50

Step-by-step explanation:

is there a picture or something there isnt much context

6 0
2 years ago
I’m confused on this answer anyone know it?
slamgirl [31]

Answer:

y=\frac{26}{7},\:x=-\frac{15}{7}

Step-by-step explanation:

\begin{bmatrix}4x+5y=10\\ -2x+y=8\end{bmatrix}\\\\\begin{bmatrix}-2\cdot \frac{10-5y}{4}+y=8\end{bmatrix}\\\\

-5+\frac{7y}{2}=8\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\-5\cdot \:2+\frac{7y}{2}\cdot \:2=8\cdot \:2\\-10+7y=16\\y=\frac{26}{7}\\

\mathrm{For\:}x=\frac{10-5y}{4}\\\mathrm{Subsititute\:}y=\frac{26}{7}\\x=\frac{10-5\cdot \frac{26}{7}}{4}\\\\

x=-\frac{15}{7}\\

7 0
3 years ago
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