Answer: A. There all 90 degrees
Step-by-step explanation:
Given: Three parallel lines are cut by a transversal and one angle is measured to be 90 degrees.
We know that if two lines cut by transversal the following pairs are equal:
- Vertically opposite angles.
- Corresponding angles.
- Alternate interior angles.
- Alternate exterior angles.
If one angles measures 90°, then its supplement would be 90°.
Then by using above properties , we will get measure of all angles as 90°.
1. The shape of cross-section is a circle.
2. The face parallel to ABCD is EFGH. Since this is a a rectangular shape,
A = L*H = 12*6 = 72 cm^2
3. The cross-section parallel to ABC is DEF with h = 12 ft, b= 5ft (where h is the height and b is the base of a right angled triangle).
Area, A = 1/2 *b*h = 1/2*5*12 =30 ft^2
4. Plane BDHF is a rectangle shape whose length is the diagonal of ABCD.
Diagonal BD = sqrt (AB^2+BD^2) = sqrt (8^2+7^2) = 10.63 cm.
Perimeter, P = 2(BD+DH) = 2(10.63+6) = 33.26 cm
X^2/2 = 7x
x^2 = 14x
x^2 - 14x = 0
A quadratic equation is of the form ax^2 + bx + c
Therefore, in 3x^2 + 5x + 7, c = 7
Answer:
If you substitute (-1,2) meaning x and y
2=3(-1)-2
2=-3-2
2= -1
Step-by-step explanation:
he's incorrect since the solution does not equal 2 on both sides
