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VLD [36.1K]
3 years ago
15

write an equation in point slope form for the line that has a slope of 9/4 and contains the point (3,-4)

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0

Answer:

y+4 = 9/4(x-3)

Step-by-step explanation:

The point slope form of an equation is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

Substituting in what we know

y--4 = 9/4(x-3)

y+4 = 9/4(x-3)

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Sphinxa [80]

Answer:

x = 9

Step-by-step explanation:

8x - 10 = 62

8x = 72

x = 9

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6 0
3 years ago
Determine the points of intersection of the line y=2x+5 and the circle x²+y²=36
Vladimir79 [104]

The two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

<h3>How to find the points of intersection?</h3>

Here we want to solve the system of equations:

y = 2x + 5

x² + y² = 36

To solve this, we need to replace the first equation into the second one:

x² + (2x + 5)² = 36

Now we can solve this for x:

x² + 4x² + 10x + 25 = 36

5x² + 10x - 11 = 0

This is a quadratic equation, to solve it we use the general formula:

x = \frac{-10 \pm \sqrt{10^2 - 4*5*(-11)} }{2*5} \\\\x = \frac{-10 \pm 17.9 }{10}

So we have two solutions for x:

x = (-10 - 17.9)/10 = -2.79

x = (-10 + 17.9)/10 = 0.79

To get the y-values of the solutions, we evaluate the linear equation in these values of x:

y = 2*(-2.79) + 5 = -0.58

y = 2*( 0.79) + 5 = 6.58

Then the two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

If you want to learn more about intersection points:

brainly.com/question/17206319

#SPJ1

5 0
2 years ago
☆pls help no one has helped me and I'm so confused! ​
motikmotik

Answer:

Step-by-step explanation:

a). \frac{5\pm\sqrt{-4}}{3} = \frac{5}{3}\pm \frac{\sqrt{-4}}{3}

               = \frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}

               = \frac{5}{3}\pm\frac{2i}{3} [Since, i = \sqrt{(-1)}]

b). \frac{10\pm\sqrt{-16}}{2} = \frac{10}{2}\pm \frac{\sqrt{-16}}{2}

                  = 5\pm \frac{4\sqrt{-1}}{2}

                  = 5 ± 2i [Since, i = \sqrt{(-1)}]

c). \frac{-3\pm \sqrt{-144}}{6} = -\frac{3}{6}\pm \frac{\sqrt{-144}}{6}

                    = -\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}

                    = -\frac{1}{2}\pm 2\sqrt{-1}

                    = -\frac{1}{2}\pm 2i [Since, i = \sqrt{(-1)}]

4 0
3 years ago
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