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kykrilka [37]
3 years ago
13

7. What is the force of tension in a rope that spins a 250 g object in a vertical circle with a radius of 50 cm if the

Mathematics
1 answer:
Phantasy [73]3 years ago
4 0
Subtract 250-50 which equals 200 and then multiply it by 3 which is 600
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For a Saturday matinee, adult tickets cost $8.50 and kids under 12 pay only $7.00. If 80 tickets are sold for a total
jolli1 [7]

Answer:

  • 30 adult tickets,
  • 50 kids tickets

Step-by-step explanation:

<u>Given</u>

  • Cost of adult ticket = $8.50
  • Cost of kids ticket = $7.00
  • Number of tickets = 80
  • Total cost = $605

Let the adult ticket be a and kids be k

<u>We got equations</u>

  • a + k = 80
  • 8.5a + 7k = 605

<u>From the first equation we get</u>

  • k = 80 -a

<u>Substituting k in the second equation</u>

  • 8.5a + 7(80 - a) = 605
  • 8.5a - 7a + 560= 605
  • 1.5a = 45
  • a = 45/1.5
  • a = 30

<u>Then finding k</u>

  • k = 80 - 30 = 50

8 0
3 years ago
Will give brainliest
Ostrovityanka [42]

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6 0
3 years ago
What is it plz help me with it ​
victus00 [196]

Answer:

isk

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which method can you use to calculate the y-coordinate of the midpoint of a vertical line segment with endpoints at(0,0) and (0,
ahrayia [7]

Answer:

(0, - 6)

Step-by-step explanation:

Since this is a vertical line then the midpoint of the y- coordinates is

\frac{1}{2}(0 - 12) = - 6

⇒ midpoint = (0, - 6 )


7 0
3 years ago
URGENT please help!!! I need a explanation please!! You own a restaurant and can reopen as long as people seated at a table are
hram777 [196]

Answer:

1) Maximum number of tables that can be kept in the dinning room is 10 tables

2)The maximum number of customers, given 6 people per table is 60 customers

Step-by-step explanation:

The parameters given are;

Distance between people seated at different tables = 6 ft

Dimension of table = 2 m by 1.5 m

Number of people at a table = 6 people

Dimension of dinning;

Width = 12 m

Length = 20 m

Dimension of entrance;

Width = 20/21*30  m

Length = 10 m

With 6 meters between tables and a table with of 1.5, we have for the arrangement in the question;

3 tables = 4.5 m

Distance between = 2 × 6 = 12

4.5 + 12 = 16 m (More room required)

With two tables, we have;

Width of tables = 2×1.5 = 3 m

Distance between = 6 m

Dining room width required = 3 + 6 = 9 m

Therefore, the maximum tables in each row = 2

Given that the dining room area extends to the entrance area, total length = 30 m.

With 4 tables we have;

Length = 4 × 2 + 6 × 3 = 26

While on the entrance side of the dinning room area which is 20 m, we have 3 tables;

Length = 3 × 2 + 6 × 2 = 18

Therefore, both arrangements are acceptable;

Just on entering by the right the length = 20/21×30 m

Therefore, with 3 tables will required number due to proximity wit the door and tables arranged along the right wall of the dinning

1) Maximum number of tables that can be kept in the dinning room = 4 + 3 + 3 = 10 tables

2)The maximum number of customers, given 6 people per table = 6×10 = 60 customers.

4 0
3 years ago
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