<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
A basket contains 12 apples and some other fruit
40% of the total fruit are apples...so 40% of the total fruit is 12..
0.40x = 12....with x being the total fruit in the basket <== ur equation
x = 12 / 0.40
x = 30....and u have 30 pieces of fruit in the basket
Answer:
n = -2
Step-by-step explanation:
add 7 to both sides
1+8n = -15
subtract 1 from both sides
8n = -16
divide both sides by 8
n = -2
Answer:
-3
Step-by-step explanation:
Technically nothing times 3 get you 16 but 3 times 5 equals 15 which is the closest answer but the answer would be 5.3