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dalvyx [7]
3 years ago
10

Solve for x 3r – 5r + 10 = 28

Mathematics
2 answers:
tester [92]3 years ago
3 0

Minus 5r equal is to 28

Rus_ich [418]3 years ago
3 0
The answer is either 23/3 or to simplify its 7 2/3
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Licemer1 [7]

Answer:

The carnival is losing (on average) $0.15 on each play

Step-by-step explanation:

To find out how much the carnival wins or looses in each play one subtract the expected value (EV) from each play from the amount charged by the carnival for each play ($0.55). If the expected value is higher than what the carnival charges, the carnival is losing money.

Expected is the sum of the payouts of each bet multiplied by its likelihood:

EV= \frac{64*0.40+25*1.15+1*9.00}{90}\\EV= 0.70

Since the expected value is higher than $0.55, the carnival is losing money, on average, on each play:

0.55-0.7 = -0.15

The carnival is losing (on average) $0.15 on each play

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Can someone help me with this please? I will mark you brainliest
lina2011 [118]

Answer:

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On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Step-by-step explanation:

6 0
3 years ago
Round 843 to the nearest ten.
alina1380 [7]
Hundreds Column:

8

Tens Column:

4

Ones Column:

3

The number 3 lies closer to 0, therefore the answer is <u>840</u>.
7 0
3 years ago
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