Upper quartile would be 4.5. The interquartile range could be 6.
I think it is -0.125.
It might also be 0.125
It would be 1.3 less than the other.
There are two ways you could go about solving this.
You could divide the length of the base (6mm) by 2 and use that to find the area or you could find the area of the whole triangle using 6mm and divide that by 2.
I will use the first method I described:
base = 6/2
base = 3 mm
height = 5.2 mm
area = bh/2
area = (3 * 5.2)/2
area = 7.8 square mm
(don't forget your units)
Using the other method would look like this:
area = bh/2
b = 6
h = 5.2
area = (6 * 5.2)/2
area = 15.6 square mm
area/2 = 7.8 square mm
As you can see either method yields the same result.
Hope this helped.
Cheers and good luck,
Brian
Answer:
distance is 14.04
Step-by-step explanation:
the distance between 2 points is the Hypotenuse of the right angled triangle of the x and y coordinate differences.
we use Pythagoras
c² = a² + b²
c = the Hypotenuse (the side of the triangle opposite to the 90 degree angle).
the x difference
-8 - 6 = -14
the y difference
-2 - -1 = -1
c² = -14² + -1² = 196 + 1 = 197
c = sqrt(197) = 14.04
