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rodikova [14]
3 years ago
6

A rope is used to pull a 5.07 kg block at constant speed 2.36 m along a horizontal floor. the force on the block from the rope i

s 3.01 n and directed 12.4° above the horizontal. what are (a) the work done by the rope's force, (b) the increase in thermal energy of the block-floor system, and (c) the coefficient of kinetic friction between the block and floor?
Physics
1 answer:
mezya [45]3 years ago
3 0
VThe historical method includes what steps?

The historical method includes what steps?


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If the Greek got Zeus is the ruler of the universe will we ever see him
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3

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If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow
Semenov [28]

Answer:

y = 2.196 m

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distance from axis of rotation, x = 0.38 m

Second Force, F = 129 N

moment arm of the second force, y = ?

Now, equating moments for the equilibrium

So,

m g × x = F x y

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y = 2.196 m

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6 0
3 years ago
an open rectangular tank 1.0 meter wide and 2.0 meter long contains gasoline to a depth of 1.5 meters. if the height of the tank
Alekssandra [29.7K]

The maximum horizontal acceleration is solved to be 4.91 m/s^2

<u />

<h3>What is acceleration?</h3>

This is a term in physics that refers to change in velocity with time.  Acceleration can be positive or negative or zero,

<u />

<u>Given data</u>

open rectangular tank

width = 1.0 m

length = 2.0 m

gasoline depth level = 1.5 m

height of the tank = 2.0 m

<h3>How to solve for maximum horizontal acceleration</h3>

lets represent the volume with x, y, and z such that z corresponds to height, y corresponds to wide or width, and x corresponds to length.  

dz / dy = - ay / ( g + az )

where

ay = acceleration in the y direction

az = acceleration in the z direction which is equal to zero

g = acceleration due to gravity

plugging in az = 0

dz / dy = - ay / ( g )

ay = - ( dz / dy ) * g

to prevent spilling

dz / dy = -  ( 1.5 - 1 ) / 1

dz / dy = -  0.5

ay = - ( - 0.5 ) * 9.81

ay = 4.91 meters per second square

Hence the maximum horizontal acceleration is solved to be 4.91 m/s^2

Read more on acceleration here: brainly.com/question/605631

#SPJ1

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