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Vitek1552 [10]
3 years ago
6

Write 5 advantages and disadvantges of force. aka. physicsaka. pull and push ​

Physics
1 answer:
USPshnik [31]3 years ago
6 0

It is becomes difficult to walk on a slippery road due to low friction. ... We can not fix nail in the wood or wall if there is no friction. ... A horse can not pull a cart unless friction furnishes him a secure Foothold. We can write on a paper or on a board.

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A 2500-kg car is being pushed up a hill at an angle of 35 degrees. Determine the gravitational
velikii [3]

Answer:

The force that pulls the car down is Wₓ = 14052.6 N and the one that pushes the car up is F = 26552.6 N

Explanation:

For this exercise we will use Newton's second law, let's set a reference system where the x axis is parallel to the plane, in the adjoint we can see the forces in the system.

           sin  35 = Wₓ / W

            cos 35 = W_y / W

            Wₓ = W sin 35

            W_y = W cos 35

            Wₓ = 2500 9.8 sin 35

             Wₓ = 14052.6 N

let's write the equations for each axis

and

Y axis  

       N-W_y = 0

       N = W_y

X axis  

       F -Wₓ = m a

       F = Wₓ + m a = mg sin 35 + m a

       F = m (a + g sin 35)

   

let's calculate

       F = 2500 (5 + 9.8 sin 35)

       F = 26552.6 N

The force that pulls the car down is Wₓ = 14052.6 N and the one that pushes the car up is F = 26552.6 N

3 0
3 years ago
Please need help on this
likoan [24]
The answer to this would be ocean floor
4 0
3 years ago
Two technicians are discussing a problem where the brake pedal travels too far before the vehicle starts to slow. Technician A s
iVinArrow [24]

Answer:

Technician A

Explanation:

If Technician B was correct, and the master cylinder is defective - then no braking action would occur.

This is not true however, as some breaking action eventually occurs, meaning it must be out of adjustment.

3 0
4 years ago
A hot air balloon moves vertically upwards at constant velocity of 1.5 m s−1 . A person standing on the ground below throws a ba
serg [7]

Answer:

idk srry

Explanation:

i wish I could help you out

8 0
3 years ago
A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. how long does h
noname [10]
The shot putter should get out of the way before the ball returns to the launch position.

Assume that the launch height is the reference height of zero.
u = 11.0 m/s, upward launch velocity.
g = 9.8 m/s², acceleration due to gravity.

The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
t(11 - 4.9t) = 0
t = 0 or t = 4.9/11 =  0.45 s

t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.

Answer: 0.45 s
7 0
3 years ago
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