When listening to someone in trouble, you should be
2 answers:
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Explanation:
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Answer:
Explanation:
Given that the temperature of of water and
of water are
at and
respectively.
Let ,
and ,
.
The specific heat capacity of water is,
.
Let the final temperature of the mixture be .
As there is no energy loss, so, the energy loss by the water at higher temperature, i.e. , will be equal to the energy gain by the water at lower temperature, i.e.
.
[ both sides divided by
]
Now, putting the given value in the above equation, we have
Hence, the temperature of the mixture will be .
Answer:
a)The volume is reduced to one-third of its original value.
Explanation:
For a gas at constant temperature, we can apply Boyle's law, which states that the product between pressure and volume is constant:
where p is the pressure and V the volume.
In our case, this law can also be rewritten as
where the labels 1 and 2 refer to the initial and final conditions of the gas.
For the gas in the problem, the pressure of the gas is tripled, so
And re-arranging the equation we find what happens to the volume:
so, the volume is reduced to 1/3 of its original value.