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Troyanec [42]
2 years ago
13

1. How can researchers, educators, and policymakers encourage journalists and others to discuss

Physics
1 answer:
Setler79 [48]2 years ago
6 0

Correlational studies do not form the  decision making or discussion because they do not offer conclusive evidence.

<h3>What are correlational findings?</h3>

The term correlational findings refers to research findings that only show the association between variables. This is a kind of research that does not establish causation but suggests a strong link between two variables.

This kind of study should not form the basis for decision making or discussion because they do not offer conclusive evidence about an issue. this kind of findings should e taken with a pinch of salt until the data is further confirmed by experimental studies.

Learn more about correlational findings:brainly.com/question/15411622

#SPJ1

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Explanation:

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3 years ago
The distance, in feet, a moving object has traveled after t seconds is given by 2t/(4 + t). find the acceleration of the object
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Hi! Let me help you!
a = (Vf - Vi)/t ; where distance d = [2(t)]/(4+t), t = 5secs, and Vi = 0 
a = [(2t)/(4+t)]/t <---- working equation
a = {[2(5)]/9}/5 <---- cancel 5
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3 years ago
A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete
Lesechka [4]

Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is 6.25\times 10^{- 3} ft/s^{2}

Solution:

As per the question:

Constant velocity of the horse in the horizontal, v_{x} = 1 ft/s

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

20^{2} + 10^{2} = l^{2}

l^{2}= 500

Now,

x^{2} + y^{2} = 500                            (1)

Differentiating equation (1) w.r.t 't':

2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0

x\frac{dx}{dt} = - y\frac{dy}{dt}

where

\frac{dx}{dt} = Rate of change of displacement along the horizontal

\frac{dy}{dt} = Rate of change of displacement along the vertical

v_{x} = velocity along the x-axis.

v_{y} = velocity along the y-axis

xv_{x} = -yv_{y}

v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s

|v_{y}| = 0.5\ ft/s

Acceleration of the hay bale is given by the kinematic equation:

v_{y}^{2} = u_{y} + 2ay

(-0.5)^{2} =0 + 2ay

0.25 = 2ay

\frac{0.25}{2y} = a

a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}

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Explanation:

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