The volume occupied by 0.118mol of He gas at a pressure of 1.05 atm and temperature of 322k is calculated by use of ideal gas equation
that is PV = nRT
P(Pressure)1.05 atm
v(volume)=?
n (number of moles)=0.118 mol
T(temperature)= 322K
from equation above volume(v)= nRT/p
volume(v) = (0.118 mol x 0.0821 L.atm/k.mol x322k) / 1.05 atm = 2.97 L
Answer:
Acidic solution used to clean a crucible
Explanation:
This liquid dissolves alcoholic solvents such as crucible, that is why it was selected as the ideal for cleaning.
Although it would be ideal to know in detail which chemical compound is the one you want to clean so that the cleaning technique has better effectiveness.
Answer:
Explanation:
You can determine the units in the final answer by identifying which of the units cancel out. Units are eliminated (cancelled out) when they are located both in the numerator and denominator of proportions being multiplied.
In this case, these units are cancelled out.....
-----> milligrams (mg) = (1st and 2nd proportions)
-----> decaliters (dL) = (1st and 3rd proportions)
-----> liters (L) = (3rd and 4th proportions)
As these units are not cancelled out, you are left with grams (g) in the numerator and milliliters (mL) in the denominator.
The final units should be represented by:
Answer:
Molecular composition of iodine heptafluoride is one iodine atom and seven fluorine atoms.
Explanation:
The molecular formula of iodine heptafluoride is and it is also known as Iodine (VII)fluoride.
According to the VSEPR theory,The geometry of the iodine heptafluoride is "petagonal bipyrmidal."
From the molecular formula of iodine heptafluoride has seven atoms of fluorine and only one atom of iodine.
Therefore, the molecular composition of iodine heptafluoride is one iodine atom and seven fluorine atoms.
Molecular geometry of a compound can be determined by drawing the Lewis structure.
Total number of electrons in ClNO = 7 + 5 +6 = 18 electrons
In the Lewis structure drawn in the image shared, we have three electrons domains around the central atom, two bonding and one lone pair. As there are three electron groups around the central atom, we expect trigonal planar geometry. But due to the presence of lone pair of electrons and repulsions between lone pair and bond pair of electrons, the molecular geometry will be bent.