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ki77a [65]
3 years ago
12

what is the volume occupied by 0.118 mol of helium gas at a pressure of 1.05 atm and a temperature of 322 K?

Chemistry
1 answer:
beks73 [17]3 years ago
6 0
  The  volume  occupied  by  0.118mol  of He  gas  at  a pressure of  1.05 atm  and  temperature  of  322k  is  calculated   by  use  of   ideal  gas    equation

that  is  PV = nRT
P(Pressure)1.05 atm
v(volume)=?
n  (number  of  moles)=0.118 mol
T(temperature)= 322K

from  equation  above volume(v)= nRT/p

volume(v) =  (0.118 mol  x  0.0821 L.atm/k.mol x322k)  / 1.05 atm =  2.97  L

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ArbitrLikvidat [17]

Answer:

\boxed{\text{3.3 mL}}

Explanation:

You must convert 30 % (m/v) to a molar concentration.

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2. Moles of NaOH  

\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}

3. Molar concentration of NaOH

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4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

c_{1}V_{1} = c_{2}V_{2}

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Data:

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Calculations:

(a) Convert millilitres to litres

V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}

(b) Calculate the volume  of dilute solution

\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}

\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}

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