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ki77a [65]
3 years ago
12

what is the volume occupied by 0.118 mol of helium gas at a pressure of 1.05 atm and a temperature of 322 K?

Chemistry
1 answer:
beks73 [17]3 years ago
6 0
  The  volume  occupied  by  0.118mol  of He  gas  at  a pressure of  1.05 atm  and  temperature  of  322k  is  calculated   by  use  of   ideal  gas    equation

that  is  PV = nRT
P(Pressure)1.05 atm
v(volume)=?
n  (number  of  moles)=0.118 mol
T(temperature)= 322K

from  equation  above volume(v)= nRT/p

volume(v) =  (0.118 mol  x  0.0821 L.atm/k.mol x322k)  / 1.05 atm =  2.97  L

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3 years ago
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Kobotan [32]

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2 years ago
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