Which of the following is not an agent of metamorphism? pressure running water hydrothermal solution

Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.

UNO [17]

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

4 0

3 years ago

What is a manipulated variable

ivanzaharov [21]

It is the independent variable because you can ‘manipulate’ or ‘change’ it.

6 0

3 years ago

Solutions of Cu2+ turn blue litmus red because of the equilibrium: Cu(H2O)62+(aq) + H2O(l) ↔ Cu(H2O)5(OH)+(aq) + H3O+(aq) for wh

Elanso [62]

Answer: The pH of 0.10 M $Cu(NO_{3})_{2}(aq)$ is 4.49.

Explanation:

Given: Initial concentration of $Cu(H_{2}O)^{2+}_{6}$ = 0.10 M

$K_{a} = 1.0 \times 10^{-8}$

Let us assume that amount of $Cu(H_{2}O)^{2+}_{6}$ dissociates is x. So, ICE table for dissociation of $Cu(H_{2}O)^{2+}_{6}$ is as follows.

$Cu(H_{2}O)^{2+}_{6} \rightleftharpoons [Cu(H_{2}O)_{5}(OH)]^{+} + H_{3}O^{+}$

Initial: 0.10 M 0 0

Change: -x +x +x

Equilibrium: (0.10 - x) M x x

As the value of $K_{a}$ is very small. So, it is assumed that the compound will dissociate very less. Hence, x << 0.10 M.

And, (0.10 - x) will be approximately equal to 0.10 M.

The expression for $K_{a}$ value is as follows.

$K_{a} = \frac{[Cu(H_{2}O)^{2+}_{6}][H_{3}O^{+}]}{[Cu(H_{2}O)^{2+}_{6}]}\\1.0 \times 10^{-8} = \frac{x \times x}{0.10}\\x = 3.2 \times 10^{-5}$

Hence, $[H_{3}O^{+}] = 3.2 \times 10^{-5}$

Formula to calculate pH is as follows.

$pH = -log [H^{+}]$

Substitute the values into above formula as follows.

$pH = -log [H^{+}]\\= - log (3.2 \times 10^{-5})\\= 4.49$

Thus, we can conclude that the pH of 0.10 M $Cu(NO_{3})_{2}(aq)$ is 4.49.

8 0

3 years ago

There are four cis,trans isomers for 2-isopropyl-5-methylcyclohexanol, where the cis,trans designations of the substituents are

andreev551 [17]

The image is attached with the answer.

<h3>What are Isomers ?</h3>

Isomers are compounds which have same empirical formula , same number of atoms are present but they have difference in arrangement if the atoms.

It is given that

There are four cis, trans isomers for 2-isopropyl-5-methylcyclohexanol

the cis, trans designations of the substituents are made relative to the oh group

The image is attached with this answer.

To know more about Isomers

brainly.com/question/13422357

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5 0

2 years ago

How many mL of 0.100 M NaCl would be required to make a 0.0365 M solution of NaCl when diluted to 150.0 mL with water?

Tatiana [17]

Answer:

54.75 mL

Explanation:

First calculate the number of moles of NaCl in the 150mL solution of NaCl

0.0365 moles should be present on 1000cm3 or 1dm3 of water.

1L = 1 dm3

1 mL = 1 / 1000 dm3

150 mL = 150/1000 dm3 = 0.15 dm3

If x moles are present in 0.15 dm3,

x/ 0.15 = 0.0365

We get x= 0.0365 × 0.15 mol

Now x amount of moles should be taken from the initial 0.100 M NaCl solution

So 0.1 moldm-3 = 0.0365× 0.15 mol / V

we get V = 0.05475 dm3

V= 0.05475 L

V= 54.75 mL

3 0

3 years ago