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Nimfa-mama [501]
3 years ago
12

What is greater 1/4 or 1/8

Mathematics
2 answers:
liraira [26]3 years ago
8 0
The answer is that 1/4 is greater.Hope this helps!!!!! :) ;)
Also if you make 1/4 into a equivalent fraction it will be 2/8.
Anna [14]3 years ago
3 0
1/4 is greater because when 1/4 and 1/8 have equal denominators, 1/4 is bigger.
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Please explain the problem to me step by step​
JulijaS [17]
<h3>Solution:</h3>

\frac{4y}{9}  -  \frac{2y}{3}  = 10 \\  =  >  \frac{4y - 6y}{9}  = 10 \\  =  >  \frac{ - 2y}{9}  = 10 \\  =  > y = 10 \times  \frac{9}{ - 2}  \\  =  > y =  - 5 \times 9 \\  =  > y =  - 45

<h3>Answer:</h3>

-45

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3 years ago
which of the ordered pairs is a solution of the given system? y=3x-2 y=-x A.(2,9)B.(1,4)C.(1/2,-1/2)
lesantik [10]

Step-by-step explanation:


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Belinda git 18 out of 20 correct on a science test what percent of the questions did Belinda get correct
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92% of the questions were correct.
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What is the area of the shaded sector?
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The area of the shaded sector is one-fourth of the area of the whole circle so:
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The area of the shaded region is 9pi units^2
6 0
3 years ago
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In a class of 30 students (x+10) study algebra, (10x+3) study statistics, 4 study both algebra and statistics. 2x study only alg
Vladimir [108]

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

6 0
3 years ago
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