Answer:
The answer to 17 is -8. 2+ = 10 - 12 = -2*4 = -8.
The answer to 18 is 28. 4^2 = 16, 7 + 1 = 9 + 3 = 12, 16 + 12 = 28.
Step-by-step explanation:
Answer:
20-5 11/12= 9 11/12
Step-by-step explanation:
we do (3 2/3 + 2 1/4+ 2 1/3 )which is
3 8/12. 2 3/12 2 4/12 (common denominator)
then add 3 8/12 and 2 3/12 and 2 1/3 to get 10 1/12 then we get 20- 10 1/12 to get a final answer of 9 11/12
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Ok first we have to find out whats 2p+p=20 combine like terms to get 3p=20 the divide 3 on each side to get p=6 2/3 then we plug in 6 2/3 to 2p-5 so 2(6 2/3) -5 so its 12.666-5 to get 7.666 so that's the answer.
