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Usimov [2.4K]
2 years ago
13

An asset is purchased on April 1st and has an annual depreciation amount of $3,600. Using the straight-line method of depreciati

on, what is the depreciation expense on December 31st?
$3,000

$2,700

$2,900

$3,240
Mathematics
2 answers:
Free_Kalibri [48]2 years ago
5 0
From April to December =9 months

the depreciation expense
3,600×(9÷12)=2,700
Vlad1618 [11]2 years ago
4 0
The answer to your question is 2,700
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Is the point (5,8) a solution to the system of equations shown below? Justify your response
AlladinOne [14]

Step-by-step explanation:

For the point (5,8) to be a solution to the equations, when you insert x=5 and y=8 , they have to equal to the given values

substituting (5,8) into 4x+y

4(5)+8

=20+8

=28

substituting(5,8) into x-y=3

5-8

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Karl’s math class is playing a number game. Each student is given a number card containing the numbers 1 to 6. The rules of the
Lena [83]

By finding the probability, we can expect that 2 out of the 30 students will win the prize.

<h3>How many of the 30 students will win the prize?</h3>

First, we should get the probability of winning this game.

Here the students select two numbers out of 6, just to make the calculations let's say that these numbers are 1 and 2.

Now, we need to get these two numbers in two balls. The probability of getting the ball with the number 1 out of the 6 balls is:

p = 1/6

The probability of getting the ball with the number 2 out of the remaining 5 balls (because we already got one) is:

q = 1/5

The joint probability is then:

P = 2*(1/6)*(1/5) = 1/15.

Where the factor 2 comes to take in account the permutations, for the case where we first draw the number 2 and then the number 1.

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(1/15)*30 = 2

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8 0
1 year ago
What is the area? Please help
Mrrafil [7]

Answer:

75

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
-3/v=-6 simply as much as possible
Aleksandr [31]
Hey!


In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

<em>Original Equation :</em>
\frac{-3}{v} = -6

<em>New Equation {Added Multiply Both Sides by V} :</em>
\frac{-3}{v} v=-6v

<em>Solution {New Equation Solved} :</em>
-3 = -6v

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

<em>Old Equation :</em>
-3 = -6v

<em>New Equation {Switched} :</em>
-6v=-3

Now we'll divide both sides by v to get v on its own.

<em>Old Equation :</em>
-6v = -3

<em>New Equation {Added Divide Both Sides by V} :</em>
\frac{-6v}{v} = \frac{-3}{v}

<em>Solution {New Equation Solved} :</em>
v =  \frac{1}{2}

<em>So, this means that in the equation \frac{-3}{v} =-6,</em>  v =  \frac{1}{2}.

Hope this helps!


- Lindsey Frazier ♥
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3 years ago
The Unit Circle
Ronch [10]

Answer:

0 is the correct answer dude

5 0
2 years ago
Read 2 more answers
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