Yes and half a dozen is 6
I know two ways that we can use in this problem, it depends on your knowledge in your math class.
The first way is using the combinatorial formula, and probability:
P = possibles outcomes from the event/ all outcomes from the experiment
Using combinatoria P = (2C2*4C1)/(6C3)
2C2 is the possibles ways to get two defectives and we calculate that:
2C2=2!/(2!*(2-2)!)=1
Then, 4C1 is the possibles ways to get 1 no defective (remember you need only 3 test and you expect 2 are defective from the question), calculating:
4C1=4!/(1!*(4-1)!)=4
And 6C3 represents the all possible ways to get 3 calculators (no matter if they defective or not), calculating:
6C3=6!/(3!*(6-3)!)=20
Apply p formula:
<span>P = (1*4)/20 = 1/5 = 0.2</span> in percertage 20%
The another way to calculate this problem is using the tree diagram or multiplication rule:
P=(2/6)*(1/5)*(4/4)=1/15 (here you are saying the order of computer, first and second defective and the last one no defective)
P=(2/6)*(4/5)*(1/4)=1/15 ( the second is no defective, and the others are defective)
P=(4/6)*(2/5)*(1/4)=1/15 (the first one is no defective and the others are defective)
Finally add the three result above, and get the answer:
<span>P=1/15+1/15+1/15 = 3/15 = 1/5 = </span>0.2
Answer:
2.22
Step-by-step explanation:
Answer:
y = 1/3(x + 5)^2 - 4
Step-by-step explanation:
The general vertex form is;
y = a(x-h)^2 + k
From the question, (h,k) are the coordinates of the vertex which is (-5,-4)
So we have
y = a(x + 5)^2 -4
So we need to get the leading coefficient
Simply substitute the point it passes through
x = -2 and y = -1
-1 = a(-2 + 5)^2 - 4
-1 = a(3)^2 -4
-1 = 9a -4
9a = 4-1
9a = 3
a = 3/9
a = 1/3
So the equation is;
y = 1/3(x + 5)^2 - 4
Answer:
its b
Step-by-step explanation:
