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torisob [31]
3 years ago
8

Subtract using the number line -1 1/3 - 1/6

Mathematics
2 answers:
statuscvo [17]3 years ago
6 0

Answer:

-5/6

Step-by-step explanation:

you can turn it into a proper fraction and you would hv -4/3 minus 1/6.then you get -5/6.

liq [111]3 years ago
3 0
-1 19/78 ...... all you have to do is go 1/6 steps up because its negative 1 1/3
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Four times the number of coins in my pocket plus five more is twenty-nine. Write an equation for the number of coins in my pocke
Lynna [10]
There are six coins already in pocket, but let’s say we don’t know it.

We would figure it out by reversing the problem. Let’s start with twenty-nine. We would subtract 5, because we are reversing. Now we have 24. Now, let’s divide by four. We would get 6.

A simpler answer would be 29 - 5 [divided by] 4 = [answer]
4 0
3 years ago
The function h is defined by h (x) = x^2 +5.<br> Find h (4a).<br> ????
rjkz [21]

Answer:

16a^2+5

Step-by-step explanation:

8 0
4 years ago
2. through: (8,5), perpendicular to y=-1/2x +4
SCORPION-xisa [38]
Perpendicular slope: flip sign and reciprocal = 2
Y = 2x + b
Plug in point (8,5)
5 = 2(8) + b
5 = 16 + b
b = -11
Equation: y= 2x - 11
7 0
3 years ago
Plz help! Question is below!
Fynjy0 [20]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Which function has an inverse function?
daser333 [38]

Answer: Option B

Step-by-step explanation:

By definition, only those functions that are one to one have an inverse function.

A function is one by one if there are not two different input values, x_1 and x_2, that have the same output value y

Note that the function f(x)= \frac{|x+3|}{5}  is not a one-to-one function

When x=2  f(x)= \frac{|2+3|}{5}=1\ ,\ \ y=1

When x=8  f(x)= \frac{|-8+3|}{5}=1\ \ ,\ y=1

Note that the function f(x)= \frac{x^4}{7}+ 27  is not a one-to-one function

When x=1 f(x)= \frac{(1)^4}{7}+27\ ,\ \ y=\frac{190}{7}

When x=-1  f(x)= \frac{(-1)^4}{7}+27\ ,\ \ y=\frac{190}{7}

Note that the function f(x)= \frac{1}{x^2}  is not a one-to-one function

When x=1 f(x)= \frac{1}{(1)^2}\ ,\ \ y=1

When x=-1  f(x)= \frac{1}{(-1)^2}\ ,\ \ y=1

Then the answer is the option B.

You can verify that The function f (x) = x ^ 5-3 is a one-to-one function and therefore its inverse is a function

5 0
3 years ago
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