Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
2 cows and 5 chickens.
Step-by-step explanation:
NOTE: This will be solved using simultaneous equations.
Let x = cows and y = chickens
1. form two equations
4x + 2y = 18 ... (1)
x + y = 7 .... (2)
2. make y (or x) the subject of one equation
x + y = 7
y = 7 - x ... (3)
3. Substitute (3) into (1)
4x + 2( 7 - x) = 18
4. solve for x
4x + 14 - 2x = 18
2x = 4
x = 2
5. Now substitute x value into equation (2)
x + y = 7
2 + y = 7
y = 5
∴ cows (x) = 2
chickens (y) = 5
Your answer would be 248 i hope this helps and please mark me as brainliest :)
Answer:
Its cost about 1.5625
if you rounded its 1.56 :)
Step-by-step explanation:
