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2 years ago

Write n as a fraction in simplest form.

Mathematics

1 answer:

muminat2 years ago

4 0

Answer:

wouldn't it be $\frac{n}{1}$ ?

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3/12 and 5/x are<br> equivalent ratios. Solve for<br> X. Pls help asap

Phoenix [80]

Answer:

3/12 and 5/x

12 times 5 is 60 so 3 times 20 shall be 60

3/12 = 5/20

4 0

2 years ago

Select whether each equation has no solution, one solution, or infinitely many solutions.

xxTIMURxx [149]

Answer:

Step-by-step explanation:

A) 5x - 7 = 5x becomes -7 = 0 if 5x is subtracted from both sides. This result is never true, so NO SOLUTION

B)3x−9=3(x−3) Performing the indicated multiplication, we get

3x - 9 = 3x - 9. This is always true, so there are INFINITELY MANY SOLUTIONS

C)2x−6=−2(x−3) Performing the indicated multiplication, we get

2x - 6 = -2x + 6. Adding 2x - 6 to both sides results in

4x - 12 = 0, or 4x = 12. Thus, the solution is x = 3. ONE SOLUTION

D)2x+6−5x=−3(x This equation is incomplete

3 0

2 years ago

Read 2 more answers

Please answer this question!! 30 points and brainliest!

Alexeev081 [22]

2x(-5x-3)

2x(-5x)= -10x and 2x(-3)= -6x

= -10x sq - 6x

-10x is sq bc you are multiplying the same variable twice

5 0

3 years ago

6. Find the sum or difference.<br> 146<br> 155<br> a. +<br> 8<br> 8

Ipatiy [6.2K]

19191020202929293994494944

5 0

2 years ago

Soft drink consumption in New Zealand. A survey commissioned by the Southern Cross Healthcare Group reported that 16% of New Zea

lidiya [134]

<h2>Answer with explanation:</h2>

Given : The proportion of New Zealanders consume five or more servings of soft drinks per week : $\hat{p}= 0.16$

a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006

b) Confidence interval for population proportion (p) :

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = Sample proportion.

n= Sample size.

z* = Critical value.

For n= 2006 , $\hat{p}= 0.16$ and critical value for 95% confidence interval : z* = 1.96

Then , the required confidence interval will be :

$0.16\pm (1.96)\sqrt{\dfrac{ 0.16(1- 0.16)}{2006}}$

$0.16\pm (1.96)\sqrt{ 0.000066999002991}$

$0.16\pm (1.96)(0.00818529186963)$

$0.16\pm 0.0160431720645$

$(0.16-0.0160431720645,\ 0.16+0.0160431720645)$

$(0.143956827935,\ 0.176043172064)\approx(0.144,\ 0.176)$

i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = $(0.144,\ 0.176)$

c) $(0.144,\ 0.176)=(0.144\times100\%,\ 0.176\times100\%)$

$=(14.4\%,\ 17.6\%)$ 176\times100\%)[/tex]

d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.

6 0

3 years ago