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3 years ago

Write n as a fraction in simplest form.

Mathematics

1 answer:

muminat3 years ago

4 0

Answer:

wouldn't it be $\frac{n}{1}$ ?

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Although the problem above may look really different or much harder than any equation we have solved before, guess what?! It’s n

defon

Answer:

4b+8 = 20

---------------

4b = 20

-------------------

b = 5

Step-by-step explanation:

We need to solve for b in the following equation:

$\frac{4b + 8}{2} = 10$

When we multiply each term by 2 the denominator cancels out:

$\displaystyle 2 \times \frac{4b + 8}{2} = 10 \times 2\\\\4b + 8 = 20$

Next, we subtract 8:

$4b +8 - 8 = 20 - 8\\4b = 20$

Final step, we isolate the variable. We cancel the multiplication on the left side when dividing by 4 on each term

$\displaystyle 4b = 20\\\\\frac{4b}{4} = \frac{20}{4}\\\\b = 5$

7 0

3 years ago

(-13x-15)-(-9x+16) what is the answer to this equation

ella [17]

−4x−31

Step-by-step explanation:

combine like terms

4 0

3 years ago

How many different 11-letter arrangements can be made using the letters in the word Firecracker?

zhenek [66]

Answer:

Total number of arrangements = 1,663,200

Step-by-step explanation:

Given:

11 - letter

FIRECRACKER

F = 1

I = 1

R = 3

E = 2

C = 2

A =1

K = 1

Find:

Total number of arrangements = ?

Computation:

Note: Repeated letter will be avoid.

$Number\ of\ arrangements = \frac{!11}{!3 \times !2 \times !2}\\\\Number\ of\ arrangements = \frac{!11}{!3 \times !2 \times !2} \\\\Number\ of\ arrangements = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3}{3 \times 2 \times 2 } \\\\Number\ of\ arrangements = 1,663,200$