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mel-nik [20]
3 years ago
5

Allison went back to school shopping with her three children. The first child needed three notebooks, four pencils, and two pens

for a total of $5.45. The second child needed 5 notebooks, two pencils, and three pens totaling $7.80. Her last child needed two notebooks, five pencils, and for pens for a total cost of $5.15. Find the cost of each item.
Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0
Write an equation system where x=cost of notebook, y=cost of pencil, z=cost of pen.
3x+4y+2z=5.45
5x+2y+3z=7.80
2x+5y+4z=7.15
Solve this system and you get x= $1.25 per each notebook, y= $0.25 per each pencil, z= $0.35 per each pen
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Which inequality has a solid boundary line when graphed?
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4th option

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An inequality using > or < has a broken boundary when graphed.

An inequality using ≥ or ≤ has a solid boundary when graphed

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6 0
3 years ago
find the least length of a rod which can be cut into exactly epual strips,each of either 36cm or 42cm in length​
Triss [41]

Step-by-step explanation:

so, we need to find the smallest common multiple of 36 and 42.

that is the smallest number I can divide both by 36 and 42 without remain.

let's use the method of basic prime factors (we start with the smallest fitting prime number - 2 is a prime number too - and divide as often as possible, then continue with the next bigger prime number, until there is nothing left to divide) :

36 / 2 = 18

18 / 2 = 9

9 / 3 = 3

3 / 3 = 1 finished

therefore,

36 = 2×2×3×3

42 / 2 = 21

21 / 3 = 7

7 / 5 does not work

7 / 7 = 1 finished

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42 = 2×3×7

to find the smallest common multiple (SCM) we check the maximum length of each prime factor sequence.

and we see 2 times 2, 2 times 3 and 1 time 7.

so, the SCM = 2×2×3×3×7 = 252.

there is no smaller number that can be divided by both 36 and 42 without remain.

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5 0
3 years ago
Please help me, GodBless.
Fed [463]

Answer:

m= 5/2

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Points: (0, 2) and (4, 12)

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m=(y2-y1)/(x2-x1)

m=(12-2)/(4-0)

m=10/4

m= 5/2

3 0
3 years ago
Read 2 more answers
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