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Elan Coil [88]
3 years ago
5

A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of a gallon of gas to go 1 mil

e.
How far can the car travel with 15 gallons? Show your reasoning.

How much gas does the car use to go 100 miles? Show your reasoning.


HELP ME PLEASE THIS QUESTION IS WORTH 65% OF MY GRADE!!!!
Mathematics
1 answer:
iragen [17]3 years ago
4 0

Answer:

20 gallons hope this helped

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Kinda confused on this question.
salantis [7]
6x+5= 9x-4
9=3x
3=x
To find RS you need to substitute x back into the equation
9(3)-4
27-4
23

23 is the answer
6 0
3 years ago
What is 4y when x -3
lord [1]

Answer:

4y-x-3  = 0

Step-by-step explanation:

 Slope = 0.500/2.000 = 0.250

 x-intercept = 3/-1 = -3.00000

 y-intercept = 3/4 = 0.75000

4 0
3 years ago
PLEASE HELP 100 points
g100num [7]
The problem on the left is going to be 1 tens and 8 ones, so 18.

The problem on the right is going to be 2 tens and 9 ones, so 29.
4 0
3 years ago
Read 2 more answers
1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
4 years ago
Which of the following expressions has a coefficient of 6 and a constant of 9?
Tcecarenko [31]
It would be C because a coefficient is always with a variable and 6 is with a variable which makes it a coefficient

Hope this helps

Have a great day/night
6 0
3 years ago
Read 2 more answers
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