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vladimir2022 [97]
2 years ago
8

Graph the solution for the following linear inequality system. Click on the graph until the final result is displayed.

Mathematics
1 answer:
aev [14]2 years ago
6 0
Graphing the inequalities
y ≥ 0 are the points above the x-axis including the points along the x-axis
y < x are the points below the line y = x
x + y < 6 are the points below the line x + y = 6

The solution to this is the region bounded by the lines connecting the points
(0, 0)
(0, 6)
(3, 3)
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You can represent an odd integer whith the expression 2n+1, where n is any integer . Write and solve an equation to find three c
oksian1 [2.3K]
Any odd number can be expressed by 2n+1.

For example,  

2n+1=111
2n=110
n=110/2=55

means that 111 is 2n+1 for n=55


Thus if an odd number is 2a+1, the next few numbers are as follows:

2a+1, 2a+2, 2a+3, 2a+4, 2a+5

So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.


Back to our problem: 

three consecutive odd numbers whose sum is 63 are:

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6n+9=63

6n=63-9=54

n=54/6=9


2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23


Answer: 19, 21, 23



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