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vivado [14]
3 years ago
11

The area of a rectangle is 352in2. If the width of the rectangle is x inches, write a function for the perimeter, P(x)

Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:2x2

Step-by-step explanation:

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I got -3.........................

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The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
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Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

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subtracting 100 from both sides

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ax^2+bx+c=0

Here in our case

a=1

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y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

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Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

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y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

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Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

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