A punch contains 60% of grape juice and the rest is lemon - lime soda ( 2 liters).
Part A:
An equation is:
0.6 x + 2 = x,
where x stays for the liters of punch.
Part B:
x - 0.6 x = 2
0.4 x = 2
x = 2 : 0.4
x = 5 liters
Grape juice = 5 - 2 = 3 liters.
Answer: There are 3 liters of grape juice in the punch.
<h2>Answer-Average rate of change(A(x)) of f(x) over a interval [a,b] is given by:</h2><h2 /><h2>A(x) = \frac{f(b)-f(a)}{b-a}A(x)= </h2><h2>b−a</h2><h2>f(b)−f(a)</h2><h2> </h2><h2> </h2><h2 /><h2>Given the function:</h2><h2 /><h2>f(x) = 20 \cdot(\frac{1}{4})^xf(x)=20⋅( </h2><h2>4</h2><h2>1</h2><h2> </h2><h2> ) </h2><h2>x</h2><h2> </h2><h2 /><h2>We have to find the average rate of change from x = 1 to x= 2</h2><h2 /><h2>At x = 1</h2><h2 /><h2>then;</h2><h2 /><h2>f(x) = 20 \cdot(\frac{1}{4})^1 = 5f(x)=20⋅( </h2><h2>4</h2><h2>1</h2><h2> </h2><h2> ) </h2><h2>1</h2><h2> =5</h2><h2 /><h2>At x = 2</h2><h2 /><h2>then;</h2><h2 /><h2>f(x) = 20 \cdot(\frac{1}{4})^2=20 \cdot \frac{1}{16} = 1.25f(x)=20⋅( </h2><h2>4</h2><h2>1</h2><h2> </h2><h2> ) </h2><h2>2</h2><h2> =20⋅ </h2><h2>16</h2><h2>1</h2><h2> </h2><h2> =1.25</h2><h2 /><h2>Substitute these in above formula we have;</h2><h2 /><h2>A(x) = \frac{f(2)-f(1)}{2-1}A(x)= </h2><h2>2−1</h2><h2>f(2)−f(1)</h2><h2> </h2><h2> </h2><h2 /><h2>⇒A(x) = \frac{1.25-5}{1}=-3.75A(x)= </h2><h2>1</h2><h2>1.25−5</h2><h2> </h2><h2> =−3.75</h2><h2 /><h2>therefore, average rate of change of the function f(x) from x = 1 to x = 2 is, -3.75</h2>
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Answer:
C. $14.95
Step-by-step explanation:
Do $13 times 15 divided by 100 and add that to $13.
Need to find:
- Perimeter of new square formed?
Solution:
- Side of smaller square = 3cm.
- Side of Bigger square = 9cm
Using formula:
- Perimeter of square = 4 × side
<u>Perimeter of smaller </u><u>square:</u>
⟹ 4 × 3
⟹ 12 cm
<u>Perimeter of Bigger square:</u>
⟹ 4 × 9
⟹ 36cm
Perimeter of new square = Perimeter of Bigger square - Perimeter of smaller square
⟹ 36 - 12
⟹ 24 cm
∴ Perimeter of new square formed is 24 cm.