Answer:
E ( 1 , -1 ) is in quadrant IV
Here are the values of the first 5 terms of 3 sequences: : 30, 40, 50, 60, 70, . . . : 0, 5, 15, 30, 50, . . . : 1, 2, 4, 8, 16,
Levart [38]
Answer:
1,2,4,8,16.
Step-by-step explanation:
they are a square root of 2 for each question. it will eventually get up higher then additive.
This question doesn’t make sense, double check you wrote it right
Answer:
Ok so here are the simple rules of doing it (very easy) cause I’m not doing it all so . when multiplying a power with The same base keep the base but add the exponents. Dividing, keep the base (if their the same if not then its already simplified same with multiplication) but SUBTRACT the exponents. Also keep the parenthesis if it’s a negative number base.
I’ll do a few.
11) a^10. 11b) 5^4
12) (-2)^2.
13) 10^2. 13b) s^6
14) -4s^5(t^6) <- [Im not sure of this one)
15) x^3(y^3)
Answer:
6
Step-by-step explanation:
If V = IR, then V = 40 * 3 in this case, which means V = 120. Quote question, "Assume voltage remains constant." This means V still equals 120 in the second scenario, which we can input into I = V / R to make I = 120 / 20 = 6.
Hope this helps!
