Answer:
45 minutes
Step-by-step explanation:
At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...
t = d/s
t = (7.5 mi)/(10 mi/h) = 0.75 h
to catch Peter.
Mitchell will catch Peter in 45 minutes.
__
<em>Alternate Solution</em>
Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:
3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter
_____
You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.
60 ft = 20 yds
Hope this helped!
Answer:
B. 0.268
Step-by-step explanation:
if there are more than half boys then girls it as t be und .5 since that's half and .018 is to low
Answer:
7.75 pounds
Step-by-step explanation:
16 ounces equals 1 pound so divide 16 by 124 to get 7.75
Answer:
Mrs. Habib will have 22.25 feet of border left after she puts border around the board.
Step-by-step explanation:
You must find the perimeter of the board and subtract it from the amount of border she has to find how much she will have left after she uses it. The formula for perimeter is
, where
the length of the board, and
the width of the board. You will add those together and multiply them by 2 because there are 4 sides to a rectangle. That means this equation will look like:

Now you can just solve for the perimeter.


The perimeter is 24 feet. That means it will take 24 feet of border to cover her board. In order to find out how much she'll have left over, just subtract 24 from the total amount of border she has.
Therefore Mrs. Habib will have 22.25 feet of border left over after she covers the bulletin board.