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Alekssandra [29.7K]

3 years ago

15

What is the solution to -4l-2x+6l=-24

1 answer:

Masteriza [31]3 years ago

4 0

Answer:

Step-by-step explanation:

-4|-2x+6|=-24 divide both sides by -4

|-2x+6|=6 rewrite twice

-2x+6=6 and -2x+6=-6

-6 -6 -6 -6

-2x=0 -2x= -12 for both equations divide both by two so...

x=0 x=6 then check it

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A bag contains yellow marbles and blue marbles, 80 in total. The number of yellow marbles is 4 less than 5 times the number of b

Anuta_ua [19.1K]

I believe it's 12 because 5*16=80. So, then you would subtract 4 from 16 and gat 12.

6 0

4 years ago

Point C is the center of dilation. Line segment B A is dilated to create line segment B prime A prime. The length of C A is 4. T

saw5 [17]

Answer:

Step-by-step explanation:

Given

See attachment for figure

$CA = 4$

$CA' = 16$

Required

The scale factor (k)

Since point C is the center of dilation, the scale factor (k) is calculated using:

$k = \frac{CA + CA'}{CA}$

So, we have:

$k = \frac{4+16}{4}$

$k = \frac{20}{4}$

$k = 5$

8 0

3 years ago

Given that (8,-1) is on the graph of f(x), find

Nikolay [14]

Answer:

(-12, -1)

Step-by-step explanation:

(8, -1) => (-2/3x, f(-2/3x))

therefore

-2/3x = 8

x = 8 *-3/2

x = -12

f(-2/3x) = -1

therefore, the corresponding point is:

(-12,-1)

5 0

2 years ago

Identify an equation in point-slope form for the line perpendicular to y = 1/4 that passes through (-2, -6)

abruzzese [7]

Perpendicular lines, slope is opposite and reciprocal

so slope of new line = - 4

passes through (-2, -6) in point-slope form

y + 6 = -4(x + 2)

Answer is C. y + 6 = -4 (x + 2)

4 0

3 years ago

What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

so

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

<u>case B)</u> point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

<u>case C)</u> point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

<u>case D)</u> point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

<u>case E)</u> point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

<u>case F)</u> point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

<u>the answer is</u>

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

3 years ago

Read 2 more answers