Has lost the ability to make wise decisions and is a risk and danger on the road
Thank you for posting your question here. Below is the answer, I hope it helps.
int number = 0;
while (stdin.hasNextInt() && number >= 0){
number =stdin.nextInt();
if (number > 100)
System.out.print(number + " ");
<span>}</span>
Let P(n) be "a postage of n cents can be formed using 5-cent and 17-cent stamps if n is greater than 63".Basis step: P(64) is true since 64 cents postage can be formed with one 5-cent and one 17-cent stamp.Inductive step: Assume that P(n) is true, that is, postage of n cents can be formed using 5-cent and 17-cent stamps. We will show how to form postage of n + 1 cents. By the inductive hypothesis postage of n cents can be formed using 5-cent and 17-cent stamps. If this included a 17-cent stamp, replace this 17-cent stamp with two 5-cent stamps to obtain n + 1 cents postage. Otherwise, only 5-cent stamps were used and n 65. Hence there are at least three 5-cent stamps forming n cents. Remove three of these 5-cent stamps and replace them with two 17-cent stamps to obtain n + 1 cents postage.Hence P(n + 1) is true.
Answer:
Complete Python code with step by step comments for explanation are given below.
Python Code:
# creating a function named scrabble_number that will take num as input argument
def scrabble_number(num):
# print the original number
print("The original number is: ",num)
# we can implement the required logic by using python built-in functions join() and zip()
scrambled = ''.join([char[1]+char[0] for char in zip(num[::2], num[1::2])])
# print the scrambled number
print("The scrambled number is: " + str(scrambled))
Driver code:
scrabble_number('123456')
Output:
The original number is: 123456
The scrambled number is: 214365
