Bytes have eight bits. 32 bits would be four bytes.
Lowercase a is decimal 97 ; upper case is decimal 65
It's easier to think of them in octal, however: a = octal 141, and A is octal 101
octal to binary is easy, each digit is three bits.
141 = 001 100 001
101 = 001 000 001
So, how many bits are changed above?
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Answer:
The program to this question can be given as:
Program:
public class Main //define class.
{
public static void main(String[] as) //define main method.
{
int n=5; //define variable n and assign positive value.
int i,j; //define variable
for (i = 7; i>=1; i--) //outer loop.
{
for (j = 0; j< i; j++) //inner loop.
{
System.out.print("*"); //print asterisks.
}
System.out.println(); //line break.
}
}
}
Output:
*****
****
***
**
*
Explanation:
The description of the above code can be given as:
- In the above java programming code firstly we define a class that is "Main". In this class we define a main method in the main method we define a variables that is "n" in this variable we assign a positive value. The we define another integer variable that is i,j this variable is used in the loop.
- Then we define a loop. for prints asterisks values in reverse triangle, we nested looping concept. In nested looping, we use in loop in this loop we use the i and j variables that print the asterisks value.
Answer:
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