Answer: Hello!
A second order differential equation has the next shape:
where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.
And is called homogeneus when g(t) = 0, so you have:
Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = = 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!