Answer:
1/2 over 7/8
Step-by-step explanation:
becauseim smartt
Let

be the amount of time it takes to perform an arm routine and

be the amount of time it takes to perform an abdominal routine. We see:


Subtracting the second equation from the first gives

. Substituting gives

, so

and

.
Thus, an arm routine takes ten minutes and an abdominal routine takes thirty minutes.
Step-by-step explanation:
there is no reason in maths only the method
f(x)= -1/2x-7 (better expressed as f(x) = (-1/2)x - 7 ) has a negative slope, so as x increases, y decreases. Answer D is correct.
Answer:
See explanation
Step-by-step explanation:
1. To rewrite the expression

use exponents property

So,

2. Why ![10^{\frac{1}{3}}=\sqrt[3]{10}?](https://tex.z-dn.net/?f=10%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B10%7D%3F)
Raise both sides to 10 power:
![(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D10%5E%7B%5Cfrac%7B1%7D%7B3%7D%5Ccdot%203%7D%3D10%5E1%3D10%5C%5C%20%5C%5C%28%5Csqrt%5B3%5D%7B10%7D%29%5E3%3D10)
So,
![(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D%28%5Csqrt%5B3%5D%7B10%7D%20%29%5E3)
3. Simplify 
Use the Quotient of Powers Property:

Then

4. Solve 
First, note that
then

Number
is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.
5. The same as option 4.