Answer:
This procedure does not result in a Binomial distribution.
Step-by-step explanation:
In a Binomial distribution there are only 2 outcomes in each trial.. In the roulette experiment there are more than 2 possible outcomes for each trial so this condition is not met.
5 x sqrt 2 + 3 sqrt 2. 15 sqrt 2 is the answer. You're welcome. ;)
If you change 3^x to 3^(x+4) you get
Evaluate for <span>x=3</span><span><span>(<span>33</span>)</span><span>(<span>3+4</span>)</span></span><span><span>(<span>33</span>)</span><span>(<span>3+4</span>)</span></span><span>=<span>189
</span></span>Evaluate for <span>x=4</span><span><span>(<span>34</span>)</span><span>(<span>4+4</span>)</span></span><span><span>(<span>34</span>)</span><span>(<span>4+4</span>)</span></span><span>=<span>648
</span></span>Evaluate for <span>x=x</span><span><span>(<span>3x</span>)</span><span>(<span>x+4</span>)</span></span><span><span>(<span>3x</span>)</span><span>(<span>x+4</span><span>)
</span></span></span>Evaluate for <span>x=<span>3x</span></span><span><span>(<span>3<span>3x</span></span>)</span><span>(<span><span>3x</span>+4</span>)</span></span><span><span>(<span>3<span>3x</span></span>)</span><span>(<span><span>3x</span>+4</span><span>)
</span></span></span>Evaluate for <span>x=<span>x+4</span></span><span><span>(<span>3<span>x+4</span></span>)</span><span>(<span><span>x+4</span>+4</span>)</span></span><span><span>(<span>3<span>x+4</span></span>)</span><span>(<span><span>x+4</span>+4</span><span>)
i did everything and idk wat u mean still .-. srry</span></span></span>