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enot [183]
3 years ago
8

What is the answer for −3x−6+(−1)

Mathematics
1 answer:
saw5 [17]3 years ago
7 0
Hi it would be -9x-1 hope that helps
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Find the restricted values of x for the following rational expression. If there are no restricted values of x, indicate "No Rest
melamori03 [73]

Given rational expression is

-\frac{8x}{8x^2+2x}

Now we need to find the restricted values if any for this rational expression.

Restricted values means the possible values of the used variable (x) that will make denominator 0 as division by 0 is not defined.

So to find the restricted values, we just set denominator equal to 0 and solve for x

8x^2+2x=0

2x(4x+1)=0

2x=0 or 4x+1=0

x=0 or 4x=-1

x=0 or x=-1/4


Hence final answer is x=0, -1/4

3 0
4 years ago
How was pre-image ABC transformed to create image AꞌBꞌCꞌ? A. 90° clockwise rotation around point C B. reflection over segment BC
slava [35]
<span>There are 4 main transformations: Rotation, Translation, Dilation and Reflection. Reflection is a transformation: flipping an object about a line. Reflection is distance-preserving transformation. The image has the same size as the original image ( in this case: ABC = A`B`C` ).The central line is called mirror line and here it is line BC. Answer: B. Reflection over segment BC.</span>
7 0
3 years ago
May you please help me with this question!
ANTONII [103]

Answer:

9/4x to the power of one plus 12y to the power of one

Step-by-step explanation:

You can add the top numbers for 9, but cant add the bottoms since they are different variables.

4 0
3 years ago
Read 2 more answers
N+3(n-1)<br> n plus three ( n minus 1
liq [111]

Answer:

3n^2+-3

Step-by-step explanation:

nxn +nx(-1) +3xn+ 3x(-1)

3 0
3 years ago
What is the other square root of 119 + 120i?
MakcuM [25]

Answer:

\sqrt{119+120 i}=\pm (12.24+i 4.90)

Step-by-step explanation:

Given

z = 119 + 120 i

Let \sqrt{119+120 i}=p+iq

Squaring both sides

119+120 i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

119=p^2-q^2...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

q=\frac{60}{p}

Substitute q in 1

119=p^2-(\frac{60}{p})^2

p^4-119p^2-(68)^2=0

Let x=p^2

x^2-119x-4624=0

x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}

x=\frac{119\pm 180.71}{2}

we take only Positive value because p^2=x

x=149.85  

p^2=149.85

thus p=\pm 12.24

q=\pm 4.90

thus,

\sqrt{119+120 i}=\pm (12.24+i 4.90)

8 0
3 years ago
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