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Sedbober [7]
3 years ago
14

Pls help I’ll give brainliest

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

<em><u>can</u></em><em><u>'t</u></em><em><u> </u></em><em><u>se</u></em><em><u>e</u></em><em><u> it</u></em><em><u> </u></em><em><u>too</u></em><em><u> </u></em><em><u>sm</u></em><em><u>all</u></em><em><u> </u></em><em><u>ta</u></em><em><u>lk</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>shot</u></em><em><u> </u></em><em><u>lit</u></em><em><u>tle</u></em><em><u> bit</u></em><em><u> </u></em><em><u>clo</u></em><em><u>se</u></em>

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Grayson baked 24 sugar cookies. His family ate 1/3 of the cookies. How many cookies did they eat? How many cookies are left?
horrorfan [7]

Answer:

His family ate 8 sugar cookies.

16 sugar cookies are left.

Step-by-step explanation:

  • His family ate 1/3 <em>of </em>the 24 sugar cookies: 1/3 x 24= 8
  • How many are left: 24-8=16

4 0
3 years ago
You have one type of nut that sells for $2.80/lb and another type of nut that sells for $9.60/lb. You would like to have 20.4 lb
max2010maxim [7]

Answer:11.396Ibs of nuts that cost $9.60/Ib and 9.014Ibs that cost $2.80/Ib

Step-by-step explanation:

First we find the cost of the supposed mixture we are to get by selling it $6.60/Ib which weighs 20.41Ibs

Which is 6.6 x 20.41 = $134.64

Now we label the amount of mixture we want to get with x and y

x = amount of nuts that cost $2.8/Ib

y = amount of nuts that cost $9.6/Ib

Now we know the amount of mixture needed is 20.41Ibs

So x + y = 20.41Ibs

And then since the price of the mixture to be gotten overall is $134.64

We develop an equation with x and y for that same amount

We know the first type of nut is $2.8/Ib

So for x amount we have 2.8x

For the second type of nut that is $9.6/Ib

For y amount we have 9.6y

So adding these to equate to $134.64

2.8x + 9.6y = 134.64

So we have two simultaneous equations

x + y = 20.41 (1)

2.8x + 9.6y = 57.148 (2)

We can solve either using elimination or factorization method

I'm using elimination method

Multiplying the first equation by 2.8 so that the coefficient of x for both equations will be the same

2.8x + 2.8y = 57.148

2.8x + 9.6y = 134.64

Subtracting both equations

-6.8y = -77.492

Dividing both sides by -6.8

y = -77.492/-6.8 =11.396

y = 11.396Ibs which is the amount of nuts that cost $9.6/Ib

Putting y = 11.396 in (1)

x + y = 20.41 (1)

x +11.396 = 20.41

Subtract 11.396 from both sides

x +11.396-11.396 = 20.41-11.396

x = 9.014Ibs which is the amount of nuts that cost $2.8/Ibs

8 0
3 years ago
1/3=4/12<br> Explain the reasoning in words.
nevsk [136]
1/3 is equal to 4/12.
1 goes into 3, 3 times, and 4 goes into 12 three times. Therefore 4/12 is also 1/3.
6 0
3 years ago
URGENT WILL MARK BRAINLIEST <br>Show your work and solve for x and y.<br>3x + y = 8<br>2x + 4y = 12​
mars1129 [50]
  • 3x+y=8--(1)

2x+4y=12

  • x+2y=6--(2)

  • (1)×1 and (2)×3

\\ \rm\Rrightarrow 3x+y=8

\\ \rm\Rrightarrow 3x+6y=18

Subtract both

\\ \rm\Rrightarrow -5y=-10

\\ \rm\Rrightarrow y=\dfrac{-10}{-5}

\\ \rm\Rrightarrow y=2

Put the value in eq(2)

\\ \rm\Rrightarrow x+2(2)=6

\\ \rm\Rrightarrow x+4=6

\\ \rm\Rrightarrow x=6-4=2

3 0
2 years ago
Read 2 more answers
Can someone simplify pls
algol [13]

we are given to simplify

\\ \ (x^6y^5)(5xy^2)(-6x^4)\\ \\

Open the bracket and write the like terms together

\\ \ =x^6y^5*5xy^2*(-6)x^4\\ \\ \ =-30x^6*x*x^4*y^5*y^2\\ \\

when the bases are same then the exponents gets added

\\ \ =-30x^{6+1+4}y^{2+5}\\ \\ \ =-30x^{11}y^7

8 0
3 years ago
Read 2 more answers
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