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Sedbober [7]
3 years ago
14

Pls help I’ll give brainliest

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

<em><u>can</u></em><em><u>'t</u></em><em><u> </u></em><em><u>se</u></em><em><u>e</u></em><em><u> it</u></em><em><u> </u></em><em><u>too</u></em><em><u> </u></em><em><u>sm</u></em><em><u>all</u></em><em><u> </u></em><em><u>ta</u></em><em><u>lk</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>shot</u></em><em><u> </u></em><em><u>lit</u></em><em><u>tle</u></em><em><u> bit</u></em><em><u> </u></em><em><u>clo</u></em><em><u>se</u></em>

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Need help with this question!
hodyreva [135]

Answer:

you have to do 52 divided by cos of 38 to get the answer of 65.99ft

8 0
3 years ago
I WILL GIVE U BRANLIEST What is the coefficient of x^2 in the simplified product of
Vikki [24]

Answer:

-14

Step-by-step explanation:

Okay first we must simplify the expression.

so this:(3x^2 + x-2)(x - 5)

becomes this:3x^3-14x^2-7x+10

then we look at the coefficient of x^2 and we see that it's -14

3 0
3 years ago
Read 2 more answers
How would the following triangle be classified?
Anna [14]

Answer:

hope this helpful

Step-by-step explanation:

isosceles right

because A light ray incident at 90° at the first face emerges at the same angle. The diagram shows five isosceles right-angled prisms. A light ray incident at 90° at the first face emerges at the same angle with the normal from the last face.

8 0
3 years ago
For the function y=400-22x, what is the rate of change
dolphi86 [110]

Answer:

-22

Step-by-step explanation:

The function y=400-22x is a linear equation in the form y=mx + b. Although they put "mx" after "b" so the equation doesn't start with a negative.

"m" is rate of change, or the slope if graphed.

The negative means "y" decreases as "x" increases. On a graph, it decreases left to right.

8 0
3 years ago
Find a cubic polynomial in standard form with real​ coefficients, having the zeros 4 and 5i. Let the leading coefficient be 1.
SCORPION-xisa [38]
If one of our zeros is 4, then the factor is x-4.  If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i.  So our 3 factors are (x-4)(x+5i)(x-5i).  We will FOIL out these factors to get the polynomial.  Let's start with the ones that contain the imaginary numbers.  Doing that mutliplication we get x^2-25i^2.  i^2 is equal to -1, so what that expression simplifies down to is x^{2} +25.  Now we will multiply in that last factor of (x-4):  (x^2+25)(x-4).  FOILing out we have x^3-4x^2+25x-100.  There you go!
3 0
3 years ago
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