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3 years ago

Take a factor out of the square root:

Mathematics

1 answer:

Andrews [41]3 years ago

3 0

Answer:

1. |y| sqrt(10)

2. |x| sqrt(x)

3. a^2 sqrt(a)

4. 4 |y|^3 sqrt(3)

5. 1/4 *|x| sqrt(3x)

Step-by-step explanation:

1. sqrt(10y^2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(y^2) sqrt(10)

|y| sqrt(10)

We take the absolute value of y because -y*-y = y^2 and the principle square root is y

2. sqrt(x^3)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(x^2) sqrt(x)

|x| sqrt(x)

3. sqrt(a^5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(a^4) sqrt(a)

a^2 sqrt(a)

4. sqrt(16 y^7)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(16) sqrt(y^6)sqrt(y)

4 |y|^3 sqrt(3)

5. sqrt(3/16x^3)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(1/16) sqrt(x^2)sqrt(3x)

1/4 *|x| sqrt(3x)

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Leto [7]

Answer:

False.

Step-by-step explanation:

If we substitute a for 6, the inequality would become 6 > 6. That is not true because 6 cannot be greater than itself.

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3 years ago

PLEASE HELP!!!

AfilCa [17]

Answer:

$h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.$

$JP=5\sqrt{3}\ cm$

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

$h=\dfrac{a\sqrt{3}}{2},$

where a is the side length.

So,

$h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.$

Therefore JP is 5√3 cm

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3 years ago

What is the range of the function graphed below? PLEASE ANSWER ASAP

jenyasd209 [6]

<h3>Answer: Choice C) $-\infty < y < 2$ </h3>

This is a more complicated way to write $y < 2$

The range is the set of all possible y outputs of a function. So we use the graph to see what y values are possible. The graph shows that y can be anything smaller than y = 2. We can't actually reach y = 2 itself due to a horizontal asymptote here.

In interval notation, the answer would be $(-\infty, 2)$ with the curved parenthesis to indicate "do not include y = 2 as part of the range".

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3 years ago

Help me pls i want to pass my math class

kati45 [8]

Answer:

The slope is -2

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2 years ago

A football player completes a pass 69.4% of the time. Find the probability that (a) the first pass he completes is the second

wlad13 [49]

Step-by-step explanation:

(a) If his second pass is the first that he completes, that means he doesn't complete his first pass.

P = P(not first) × P(second)

P = (1 − 0.694) (0.694)

P ≈ 0.212

(b) This time we're looking for the probability that he doesn't complete the first but does complete the second, or completes the first and not the second.

P = P(not first) × P(second) + P(first) × P(not second)

P = (1 − 0.694) (0.694) + (0.694) (1 − 0.694)

P ≈ 0.425

P = P(not first) × P(not second)

P = (1 − 0.694) (1 − 0.694)

P ≈ 0.094

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3 years ago