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3 years ago

8

The demon, khan academy, is haunting me. Please excoricse this math demon for me for a great payment of 5 stars, thanks, and a b

rainlist if two people wish to excorcise it.
Today's opponent is this circle. Please save my soul.

1 answer:

maks197457 [2]3 years ago

8 0

Answer:

3.14

Step-by-step explanation:

Formula for the area of a circle:

A = πr^2

put in the radius into the equation,

A = π(1)^2

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artcher [175]

Answer:

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Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

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