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3 years ago

F(x) = x 2 + 2 F(x2) =

1 answer:

6 0

$\bf f(x)=x^2+2\qquad \qquad f\left( \boxed{x^2} \right)=\left( \boxed{x^2} \right)^2~+~2
\\\\\\
f(x^2)=x^{2\cdot 2}+2\implies f(x^2)=x^4+2$

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The sum of three consecutive odd integers is 339. what are the integers?

Bumek [7]

339/3 = 113, the middle number
average is 113 so 111, 113 and 115

4 0

3 years ago

Y=sqrt(x)(8x-5) find the derivative

garri49 [273]

Answer:

$\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

General Formulas and Concepts:

Algebra I

Exponentials [Fractions] - Are radicals
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x}(8x - 5)$

Step 2: Differentiate

$\displaystyle f(x) = \sqrt{x}, \ g(x) = (8x - 5)$

Product Rule: $\displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Rewrite: $\displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{1 - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{0}$
Rewrite: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8$
Multiply: $\displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}$
Rewrite: $\displaystyle y' = \frac{8x + 5}{2\sqrt{x}} + 8\sqrt{x}$
Add/Rewrite: $\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

3 0

3 years ago

Pls someone help me.

puteri [66]

AB=EF

ABEF=ABF+AEF

NOW CONTINUES THE SOLUTION

4 0

3 years ago

9. help with this question o dont get it

Serjik [45]

I hope this helps you

8 0

4 years ago

Read 2 more answers

Jane and Miguel are siblings. They go to different schools. Jane walks 6 blocks east from home. Miguel 8 blocks north. How many

Firlakuza [10]

For this case we can model the problem as a rectangle triangle.
We have two sides.
We want to find the hypotenuse of the triangle.
We have then:
h = root ((a) ^ 2 + (b) ^ 2)
Substituting values we have:
h = root ((6) ^ 2 + (8) ^ 2)
h = root (36 + 64)
h = root (100)
h = 10
Answer:
If you could walk straight from one school to the other, the 2 schools would be at:
h = 10 blocks

5 0

3 years ago