3 years ago

F(x) = x 2 + 2 F(x2) =

1 answer:

6 0

$\bf f(x)=x^2+2\qquad \qquad f\left( \boxed{x^2} \right)=\left( \boxed{x^2} \right)^2~+~2
\\\\\\
f(x^2)=x^{2\cdot 2}+2\implies f(x^2)=x^4+2$

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Read 2 more answers

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Answer:

The correct answer is option 3.

Step-by-step explanation:

Given : ΔPQR, QM is altitude of the triangle

PM = 8

MR = 18

To find = QM

Solution :

PR = 8 + 18 = 26

Let, PQ = x , QR = y, QM = z

Applying Pythagoras Theorem in ΔPQR

$PQ^2+QR^2=PR^2$

$x^2+y^2=(26)^2$ ..[1]

Applying Pythagoras Theorem in ΔPQM

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$8^2+z^2=(x)^2$ ..[2]

Applying Pythagoras Theorem in ΔQMR

$MR^2+QM^2=QR^2$

$18^2+z^2=(y)^2$ ..[3]

Putting values of $x^2$ and $y^2$ from [2] and [3 in [1].

$8^2+z^2+18^2+z^2=(26)^2$

$2z^2=(26)^2-(8)^2-(18)^2$

$2z^2=288$

$z^2=144$

z = ±12

z = 12 = QM ( ignoring negative value)

The length of QM is 12.

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3 years ago

<img src="https://tex.z-dn.net/?f=x%2B0.08%2B3.21%5Cleq%2060" id="TexFormula1" title="x+0.08+3.21\leq 60" alt="x+0.08+3.21\leq 6

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Answer:

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Step-by-step explanation:

because these are the remaining digits :D

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