Pure metals possess few important physical and metallic properties, such as melting point, boiling point, density, specific gravity, high malleability, ductility, and heat and electrical conductivity. These properties can be modified and enhanced by alloying it with some other metal or nonmetal, according to the need.
Alloys are made to:
Enhance the hardness of a metal: An alloy is harder than its components. Pure metals are generally soft. The hardness of a metal can be enhanced by alloying it with another metal or nonmetal.
Lower the melting point: Pure metals have a high melting point. The melting point lowers when pure metals are alloyed with other metals or nonmetals. This makes the metals easily fusible. This property is utilized to make useful alloys called solders.
Enhance tensile strength: Alloy formation increases the tensile strength of the parent metal.
Enhance corrosion resistance: Alloys are more resistant to corrosion than pure metals. Metals in pure form are chemically reactive and can be easily corroded by the surrounding atmospheric gases and moisture. Alloying a metal increases the inertness of the metal, which, in turn, increases corrosion resistance.
Modify color: The color of pure metal can be modified by alloying it with other metals or nonmetals containing suitable color pigments.
Provide better castability: One of the most essential requirements of getting good castings is the expansion of the metal on solidification. Pure molten metals undergo contraction on solidification. Metals need to be alloyed to obtain good castings because alloys
At 45.35 c cause of how you multiply the division
I think the answer to that is B
Answer:
Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.
Explanation:
Answer:
11.3 g/cm³
Explanation:
Data Given:
Diameter of lead ball = 10.0 mm
Convert mm to cubic centimeter (cm³)
1 mm = 0.1 cm
So,
10.0 mm = 10.0 x 0.1 = 1 cm
mass of lead ball = 5.910 g
density of of lead ball =?
Solution:
To find density formula will be used
d = m/V ...........(1)
where
d = density
m = mass
V = volume
So,
To find the density of the lead ball (sphere), first we have to find volume of the ball.
To find volume of the ball following formula will be used
V = 4 . π . r³/ 3 ..............(2)
where
π = 3.14
r = radius
So,
as
So, radius will be
r = 1 cm / 2
r = 0.5 cm
Now put values in formula 2
V = (4)(3.14)(0.5cm)³/ 3
V = (12.56)(0.125 cm³) /3
V = 1.57 cm³/3
V = 0.523 cm³
So, the volume of the lead ball is 0.523 cm³
Now put values in equation 1
d = m/V
d = 5.910 g / 0.523 cm³
d = 11.3 g/cm³
Density of the lead ball = 11.3 g/cm³
