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Elenna [48]
3 years ago
7

Sodium hydroxide, NaOH, is a strong base that is used in industrial synthesis and processes such as making paper.

Chemistry
2 answers:
geniusboy [140]3 years ago
8 0
No' of molecules divide by avogadro number , 6×6.023×10^23 so (2.2×10^22)÷(6.023×10^23)
= 0.03653 moles
moles × Molar mass = mass
n×Mr=m
0.03653×40 = 1.46 grams
yuradex [85]3 years ago
6 0

Answer:

1.46 g

Explanation:

For this exercise we need the Avogadro’s number that represents the number of molecules that has a mole of a substance and is value is 6.022x10^23. That is to say that 1 mole of NAOH has  6.022x10^23 molecules and by a rule of three we have:

1 mole NaOH ----------- 6.022x10^23 molecules

         X             ----------- 2.20x10^22 molecules

X=\frac{(2.20x10^{22}molecules)(1moleNaOH)}{6.022x10^{23}molecules}

X = 0.0365 moles NaOH

Then, 2.20x10^22 molecules of NaOH represent 0.0365 moles of NaOH.

To find the mass we use another rule of three with the NaOH molar mass:

1 mole NaOH             ------ 40.0 g

0.0365 moles NaOH ------ X

X=\frac{(0.0365 moles NaOH)(40.0 g)}{1 mole NaOH}

X= 1.46 g

So, 0.0365 moles of NaOH have a mass of 1.46 g or 2.20 ×10^22 molecules of NaOH have a mass of 1.46 g

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Answer:

1. K_eq = [Ca^{2+][OH^-]^2 = K_{sp}

2. a. No effect;

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c. Products;

d. Reactants

Explanation:

1. Equilibrium constant might be written using standard guidelines:

  • only aqueous species and gases are included in the equilibrium constant excluding solids and liquids;
  • the constant involves two parts: in the numerator of a fraction we include the product of the concentrations of products;
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  • the concentrations are raised to the power of the coefficients in the balanced chemical equation.

Based on the guidelines, we have two ions on the product side, a solid on the left side. Thus, the equilibrium constant has the following expression:

K_eq = [Ca^{2+][OH^-]^2 = K_{sp}

2. a. In the following problems, we'll be considering the common ion effect. According to the principle of Le Chatelier, an increase in concentration of any of the ions would shift the equilibrium towards the formation of our precipitate.

In this problem, we're adding calcium carbonate. It is insoluble, so it wouldn't have any effect on the equilibrium.

b. Sodium carbonate is completely soluble, it would release carbonate ions. The carbonate ions would combine with calcium cations and more precipitate would dissolve. This would shift the equilibrium towards formation of the products to reproduce the amount of calcium cations.                                      

c. HCl would neutralize calcium hydroxide to produce calcium chloride and water, so the amount of calcium ions would increase, therefore, the products are favored.

d. NaOH contains hydroxide anions, so we'd have a common ion. An increase in hydroxide would produce more precipitate, so our reactants are favored.

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4 years ago
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For example, Hydrogen has only one proton, however, if you were to add say 78 more protons, you'd get gold!


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2 years ago
A chemist dissolves 581.1mg of pure perchloric acid in enough water to make up 150 ml of solution. Calculate the pH of the solut
algol [13]

<u>Answer:</u> The pH of the solution is 1.41

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of perchloric acid = 581.1 mg = 0.5811 g   (Conversion factor:  1 g = 1000 mg)

Molar mass of perchloric acid = 100.5 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

\text{Molarity of perchloric acid}=\frac{0.5811\times 1000}{100.5\times 150}\\\\\text{Molarity of perchloric acid}=0.0385M

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To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.0385M

Putting values in above equation, we get:

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