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Elenna [48]
3 years ago
7

Sodium hydroxide, NaOH, is a strong base that is used in industrial synthesis and processes such as making paper.

Chemistry
2 answers:
geniusboy [140]3 years ago
8 0
No' of molecules divide by avogadro number , 6×6.023×10^23 so (2.2×10^22)÷(6.023×10^23)
= 0.03653 moles
moles × Molar mass = mass
n×Mr=m
0.03653×40 = 1.46 grams
yuradex [85]3 years ago
6 0

Answer:

1.46 g

Explanation:

For this exercise we need the Avogadro’s number that represents the number of molecules that has a mole of a substance and is value is 6.022x10^23. That is to say that 1 mole of NAOH has  6.022x10^23 molecules and by a rule of three we have:

1 mole NaOH ----------- 6.022x10^23 molecules

         X             ----------- 2.20x10^22 molecules

X=\frac{(2.20x10^{22}molecules)(1moleNaOH)}{6.022x10^{23}molecules}

X = 0.0365 moles NaOH

Then, 2.20x10^22 molecules of NaOH represent 0.0365 moles of NaOH.

To find the mass we use another rule of three with the NaOH molar mass:

1 mole NaOH             ------ 40.0 g

0.0365 moles NaOH ------ X

X=\frac{(0.0365 moles NaOH)(40.0 g)}{1 mole NaOH}

X= 1.46 g

So, 0.0365 moles of NaOH have a mass of 1.46 g or 2.20 ×10^22 molecules of NaOH have a mass of 1.46 g

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. Sulfur dioxide can be produced in the laboratory by the reaction of hydrochloric acid and a sulfite salt such as sodium sulfit
shutvik [7]

Answer:

Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g

Explanation:

SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.

        the balanced chemical equation is as follows

                       Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O

Moles of Na₂SO₃ = \frac{Mass}{Molecular mass} =\frac{25}{126} = 0.198

Moles of HCl = \frac{mass}{molecular mass}=\frac{22}{36.5}= 0.6

using mole ratio method to find limiting reagent

      For sodium sulfite \frac{mole}{stoichiometry}  = \frac{0.198}{1}= 0.198

 for HCl \frac{mole}{stoichiometry}  = \frac{0.6}{2}= 0.3

since <u>sodium sulfite</u> is <u>limiting reactant</u> for above chemical reaction

1 mole of Na₂SO₃ produce 1 mole of SO₂

0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂

∴ Mass of SO₂ produce = mole x molar mass of SO₂

                                       = 0.198 x 64

                                       = 12.672 g

8 0
3 years ago
In a particular redox reaction, Cr is oxidized to CrO42– and Cu2 is reduced to Cu . Complete and balance the equation for this r
Alisiya [41]
<span> Cr + Cu2+ = CrO42- + Cu+

</span>
8 0
3 years ago
The
Georgia [21]

Answer:

Elements

Explanation:

The  <u> elements</u> which are represented by a single uppercase letter, or represented by an uppercase letter followed  by a lowercase letter. This tells you the types of <u>elements</u> in the compound.

Elements are one of the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means. They are made up of small indivisible particles called atoms, all having the same number of protons.

6 0
3 years ago
Why might it be important to follow the chain of custody when handling evidence?
Ierofanga [76]

Answer:

To keep a record of who has the evidence and when

Explanation:

Don't want anyone tampering with it, hope this helps!!!

5 0
2 years ago
Draw the mechanism of the slow step that occurs in both first-order substitution and first-order elimination reactions for (R)-3
BartSMP [9]

Answer:

see explaination

Explanation:

We are given the (R)-3-bromo-2,3-dimethylpentane and asking to draw the curved arrow which is the showing the mechanism for first-order substitution and first-order elimination reactions. We know the formation of carbocation is the rate determining step in the first-order substitution and first-order elimination reactions.

So in the (R)-3-bromo-2,3-dimethylpentane there is –Br gets removed and formed the tertiary carbocation which is more stable, so the curved arrows in Box 1 to depict the flow of electrons and intermediate in Box 2.

Check attachment

7 0
3 years ago
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