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yawa3891 [41]
3 years ago
8

Which product would form if chlorine gas was bubbled through a solution of sodium bromide

Chemistry
2 answers:
Lynna [10]3 years ago
7 0

Answer:

The products are sodium chloride (NaCl) and bromine (Br_2)

Explanation:

Hi, when the chlorine gas is bubbled it produces a redox reaction because of its high reactivity with the sodium compared to the bromine.

So you will have to hemireactions:

2Br^- \longrightarrow Br_2

Cl_2 \longrightarrow 2Cl^-

Combining both equations and adding the sodium:

2Br^- + Cl_2 + 2Na^+ \longrightarrow 2Cl^- +2Na^+ Br_2

2NaBr + Cl_2 \longrightarrow 2NaCl + Br_2

Jobisdone [24]3 years ago
3 0
This is what is normally termed a single replacement reaction, although don't hold me to that. It could have changed to something more modern.

Cl_{2} + NaBr \longrightarrow Br_{2} + NaCl
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g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass.
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Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

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Hydrogen (H) = 4.58%

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The empirical formula for the compound can be obtained as follow:

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O = 54.50%

Divide by their molar mass

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O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

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The empirical formula for the compound is C3H4O3

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</span>Change in freezing point from pure solvent to solution: ΔT =i · Kf · m.
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</span>m -  molality, moles of solute per kilogram of solvent.
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